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blagie [28]
2 years ago
8

Can you please help me

Mathematics
1 answer:
Mandarinka [93]2 years ago
8 0

Answer:  Attached.

Step-by-step explanation:

Either solve the equations directly, or graph them and look for the point of intersection.  

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Choose yes or no to tell whether the expression represents a 20% discount off the price of an item that originally costs d dolla
tester [92]

Answer:

Option A and C is correct.

Step-by-step explanation:

Discount is defined as a reduced price on something being sold or at a price lower than that item is normally sold for.

For a 20% discount,

Given:

Initial prices = $ d

Discounted price = % discount × original/initial cost

= 20/100 × d

= 0.2 × d

Selling price = original cost - discounted price

= d - 0.2d

= 0.8 × d

= 0.8d

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3 years ago
Carolyn watched two movies with her brother. They watched the first movie from 1:38 p.m. to 2:55 p.m. and the second movie from
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Answer:

They watched movies for 2 hours and 52 minutes.

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3 years ago
Points (4,2) and (5,1) lie on line J. what is the slope of the line that is parallel to J?
Shtirlitz [24]
Two lines that are parallel have the same slope.  Thus, find the slope of the line (J) thru (4,2) and (5,1), and that will be the answer to your question.
         2-1           1
m = --------- = ------ = -1 (answer)
         4-5          -1
5 0
3 years ago
What is the inverse of 2(x+4)^2+8
Sedaia [141]
Find the inverse, interchange the variables to solve for y
f-1 (x)=-\frac{8- \sqrt[]{_2(-8+x)} }{2} ,\frac{8+ \sqrt{2(-8+x)} }{2}
3 0
3 years ago
A communications company offers a variety of calling card options. Card A has a 30¢ connection fee and then costs 2¢ per minute.
arlik [135]

Answer:

The length of the call that would cost the same with both cards is 5 minutes.

Step-by-step explanation:

Hi there!

The cost with card A can be expressed as follows:

cost A = 30 + 2 · m

Where "m" is the length of the call in minutes.

In the same way, the cost of card B will be:

cost B = 10 + 6 · m

Where "m" is the length of the call in minutes.

We have to find the value of "m" for which the call would cost the same with both cards.

Then:

cost A = cost B

30 + 2 · m = 10 + 6 · m

Subtract 10 and 2 · m to both sides of the equation:

30 - 10 =  6 · m - 2 · m

20 = 4 · m

Divide by 4 both sides of the equation:

20/4 = m

5 = m

The length of the call that would cost the same with both cards is 5 minutes.

Have a nice day!

3 0
3 years ago
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