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Snezhnost [94]
3 years ago
14

If you roll a regular number cube what is the theoretical probability of rolling a three

Mathematics
1 answer:
yarga [219]3 years ago
7 0

Answer:1 out of 6

Step-by-step explanation: they are 6 figures in a dice and 1 three

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Patrick purchased four new tires that were regularly priced at $95.99 each, but are on sale for $20 off per tire. If the sale ta
lbvjy [14]

$ 325.2372 will be charged on Patrick's Visa card.

<u><em>Explanation</em></u>

The regular price of each tire is $95.99 and the discount amount is $20 per tire.

So, the selling price of each tire will be: (95.99-20)dollar=75.99 dollar

and the total <u>selling price of 4 tires</u> = (75.99*4)dollar=303.96 dollar

The sale tax is 7%. So, the <u>amount of sale tax</u> = 7\% of 303.96 = (0.07*303.96)dollar = 21.2772 dollar

So, the total charge on Patrick's Visa card will be: (303.96+21.2772)dollar = 325.2372 dollar

5 0
3 years ago
George went to the supermarket and he bought bananas for his monkeys. They were $5.99. He got a family discount because his wife
Solnce55 [7]

Answer:

5.74

Step-by-step explanation:

6 0
3 years ago
can anyone plz help me? i have to explain and put the formula and answer the questions and i need help :(
Effectus [21]

Answer:

This is your answer. If I'm right so,

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6 0
3 years ago
Here are the prices of five new pairs of hockey skates, in dollars: 59, 60, 65, 99, 175. The standard deviation is about $49. If
Phoenix [80]

Answer:

The standard deviation of the new data will be increased as compared to the previous standard deviation of the data.

Step-by-step explanation:

The prices are given to be : 59, 60, 65, 99, 175

Standard deviation = $49

Now, if we add or subtract any constant value to each of the terms then the standard deviation remains unchanged.

But, we add a new price in the given data that is $450

\text{New standard deviation = }\sqrt{\frac{\sum (\bar{x}-x_i)^2}{n}}\\\\\bar{x}\text{ is the mean of data after adding 450 and}\\x_i\text{ are the price values of the sample data}

Hence, Standard deviation is calculated to be 139.5

Therefore, the standard deviation of the new data will be increased as compared to the previous standard deviation of the data.

6 0
3 years ago
Read 2 more answers
A distribution of grades in a course where A=4, B=3, etc.
xenn [34]

Answer:

a. P(x= at least 2)= 1- P(no pass)= 1- 0.27= 0.73

b. 0.55

c. Expected Value = mean = 2.35 which is more than C grade that is grade B

d. variance= 1.5675

standard deviation =1.252

e. Their grade would be from (73- 100)

or 3 as it has the highest probability

Step-by-step explanation:

                       X      P(X)          X .P(X)         X²     X².P(X)

                        0       0.1                 0            0           0

                         1        0.17             0.17         1           0.17

                        2       0.21             0.42         4         0.84

                        3       0.32            0.96          9         2.88

<u>                          4       0.2               0.8           16       3.2  </u>

<u>∑                     10          1                   2.35         30     7.09</u>

Let X represent an event that the student has passed with at least a 2.

The probability of not passing (or below 2) is 0.1+ 0.17= 0.27

Then using law of complementation

a.  P(x= at least 2)= 1- P(no pass)= 1- 0.27= 0.73

b. Let Y represent the event that  a student has an A (4) given that he has passed the class with at least a C (2)

P(x)= 0.73

P(A)= 0.4

P(Y)= P(A)/P(X)= 0.4/0.73=0.55

c. Expected value= mean = 2.35 which is greater than C , Hence grade B

First we find the mean ∑X.P(X)= 2.35

d. Variance =  ∑X².P(X)   -  (∑X.P(X)²= 7.09- (2.35)² = 7.09- 5.5225=1.5675

 Standard Deviation = square root of Variance = √1.5675= 1.252

e. P(all pass) = P(A) +P(B) +P(C)= 0.2+ 0.32+ 0.21= 0.73

7 0
4 years ago
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