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mina [271]
3 years ago
13

The graph to answer the question and the answer choices.

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0

Answer:

  y ≥ 3x -1; x +3y ≤ 6

Step-by-step explanation:

Both lines are solid, so the only viable choices are those with "or equal to" in the comparison operators: the 2nd and 4th choices.

The line with a slope of +3 is shaded <u><em>above</em></u> the line, so that will correspond to the inequality ...

  y ≥ 3x -1 . . . . . . . . . . found only in the 4th choice.

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Suppose you buy a 1.25-pound package of ham at $5.20 per pound. (a) What fraction of a pound did you buy? (b) How much money did
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a) you bought 1 1/4 pound of ham
b) $6.50
1.25 x $5.20=$6.50
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Which statement is false?
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Answer:Choice A)  All points with an x-value of 3 are located in Quadrant I.

We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.

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Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of
ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is A(t) = 810(0.74)^t

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that A(24) = (1-0.26)A(0) = 0.74A(0); We use this to find r.

A(t) = A(0)(1-r)^t

0.74A(0) = A(0)(1-r)^{24}

(1-r)^{24} = 0.74

\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}

1 - r = (0.74)^{\frac{1}{24}}

1 - r = 0.9875

r = 1 - 0.9875 = 0.0125

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that A(0) = 810

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

A(t) = A(0)(1-r)^t

A(t) = 810(1 - 0.26)^t

A(t) = 810(0.74)^t

The function to represent the mass of the sample after t days is A(t) = 810(0.74)^t

5 0
3 years ago
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