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3 years ago

The graph to answer the question and the answer choices.

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

7 0

Answer:

y ≥ 3x -1; x +3y ≤ 6

Step-by-step explanation:

Both lines are solid, so the only viable choices are those with "or equal to" in the comparison operators: the 2nd and 4th choices.

The line with a slope of +3 is shaded above the line, so that will correspond to the inequality ...

y ≥ 3x -1 . . . . . . . . . . found only in the 4th choice.

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Determine the zeros of the expression -16t^2-8t+24.

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3 years ago

An empty truck. A crate of apples was then loaded onto the same truck. If the total weight load

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3 years ago

Which points are solutions to the linear inequality y < 0.5x + 2? Select three options.

zubka84 [21]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

X=6{2+3[2(7-3)+(7+1)-5]} can someone help?

erma4kov [3.2K]

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3 years ago

A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5

Elodia [21]

Answer:

7.3% percentage of the bearings produced will not be acceptable.

Step-by-step explanation:

Consider the provided information.

Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.

Let X is the normal random variable which represents the diameter of bearing.

Thus, 0.500-0.004<X<0.500+0.004

0.496<X<0.504

The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.

Use the Z score formula: $\frac{X-\mu}{\sigma}$

Therefore

$\frac{0.496-0.499}{0.002}\leq z\leq \frac{0.504-0.499}{0.002}$

$\frac{-0.003}{0.002}\leq z\leq \frac{0.005}{0.002}$

$-1.5\leq z\leq 2.5$

Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.

$P(-1.5\leq z\leq 2.5)=0.9938-0.0668=0.9270$

We need to find the percentage of the bearings produced will not be acceptable.

So subtract it from 1 as shown.

1-0.9270=0.073

Hence, 7.3% percentage of the bearings produced will not be acceptable.

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4 years ago