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Sphinxa [80]
2 years ago
12

23m 21m 37m 39mI don't really understand this can I get some help, please?​

Mathematics
1 answer:
vampirchik [111]2 years ago
7 0

Answer:

what is the question? I don't get what the problem is saying

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Graph the line with slope 4 and y-intercept -9
Monica [59]

go down to (0, -9) on the graph, from there go up four and over one and plot the next point, up four over one again, and repeat

7 0
3 years ago
Convert (CAB) 16 to decimal<br><br>need help asap
Mrrafil [7]

Remark

So CAB is a base 16 number? I hope that's correct. I'll treat it that way. If I am incorrect, please leave a note and I'll modify my answer accordingly.

Expand

A = 10 in decimal

B = 11  in decimal

C = 12 in decimal

B is the "units" value in decimal it is 11

A is the "tens" value or 12 place and in decimal you would get 12 * 10 = 120

C is the "hundreds" value or 12^2 place and in decimal you would get 144*12 =1728

Now you need to all all three results together. 11 + 120 + 1728 = 1850

Answer

(CAB)_16 = 1850 in decimal

6 0
3 years ago
Read 2 more answers
A candy store owner wants to mix some candy costing $1.25 a pound
maria [59]

The candy store owner should use 37.5 pounds of the candy costing $1.25 a pound.

Given:

  • Candy costing $1.25 a pound is to be mixed with candy costing $1.45 a pound
  • The resulting mixture should be 50 pounds of candy
  • The resulting mixture should cost $1.30 a pound

To find: The amount of candy costing $1.25 a pound that should be mixed

Let us assume that the resulting mixture should be made by mixing 'x' pounds of candy costing $1.25 a pound.

Since the total weight of the resulting mixture should be 50 pounds, 'x' pounds of candy costing $1.25 a pound should be mixed with '50-x' pounds of candy costing $1.45 a pound.

Then, the resulting mixture contains 'x' pounds of candy costing $1.25 a pound and '50-x' pounds of candy costing $1.45 a pound.

Accordingly, the total cost of the resulting mixture is 1.25x+1.45(50-x)

However, the resulting mixture should be 50 pounds and should cost $1.30 a pound. Accordingly, the total cost of the resulting mixture is 1.30 \times 50

Equating the total cost of the resulting mixture obtained in two ways, we get,

1.25x+1.45(50-x)=1.30 \times 50

1.25x+72.5-1.45x=65

0.2x=7.5

x=\frac{7.5}{0.2}

x=37.5

This implies that the resulting mixture should be made by mixing 37.5 pounds of candy costing $1.25 a pound.

Learn more about cost of mixtures here:

brainly.com/question/17109505

4 0
3 years ago
Read 2 more answers
If f(x)=2x^3-6x^2-16x-20f(x)=2x *3 −6x *2−16x−20 and f(5)=0, then find all of the zeros of f(x)f(x) algebraically.
mihalych1998 [28]

The zeros of the cubic function f(x) = 2x³ - 6x² - 16x - 20 are given as follows:

x = 5, x = -1 + i, x = -1 - i.

<h3>How to obtain the solutions to the equation?</h3>

The equation is defined by the rule presented as follows:

f(x) = 2x³ - 6x² - 16x - 20.

One solution for the equation is given as follows:

x = 5.

Because f(5) = 0.

Then (x - 5) is a linear factor of the function f(x), which can be written as follows:

2x³ - 6x² - 16x - 20 = (ax² + bx + c)(x - 5).

This is because the product of a linear function and a quadratic function results in a cubic function.

Now we expand the right side to begin finding the coefficients of the quadratic function that we are going to solve to find the remaining zeros:

2x³ - 6x² - 16x - 20 =  = ax³ + (b - 5a)x² + (c - 5b)x - 5c.

Then these coefficients are obtained comparing the left and the right side of the equality as follows:

  • a = 2.
  • -5c = -20 -> c = 4.
  • b = -6 + 5a = 4.

Hence the equation is:

2x² + 4x + 4.

Using a quadratic equation calculator, the remaining zeros are given as follows:

  • x = -1 + i.
  • x = -1 - i.

More can be learned about the solutions of an equation at brainly.com/question/25896797

#SPJ1

8 0
1 year ago
If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)
sertanlavr [38]

Answer:

Final answer is g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}.

Step-by-step explanation:

given functions are f(x)=x-6 and g\left(x\right)=\frac{1}{2x\left(x+3\right)}.

Now we need to find about what is the value of g\left(x\right)*f\left(x\right).

g\left(x\right)*f\left(x\right) simply means we need to multiply the value of  f(x)=x-6 and g\left(x\right)=\frac{1}{2x\left(x+3\right)}.

g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)

g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}

Hence final answer is g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}.

5 0
3 years ago
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