substitution and elimination means that you need to use one equation and substitute it in place of some variable in the other equation.
Consider the above two equations.
Take equation 1, which is 4x-2y=22 => x=(22+2y)/4
substitute the x value gained above in equation 2.
so, 2((22+2y)/4)+4y=6
22+2y+8y=12 => 10y = -10 => y= -1.
Substitute y= -1 in x value obtained in the beginning.
So, x= (22 - 2)/4 => 5.
There fore, x= 5 and y= -1
Hope it helps.
Answer:
x = -2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
8x + 4(x - 3) = 4(6x + ) -4
8x +(4)(x) + (4)(-3) = (4)(6x) + (4)(4) + -4 (distribute)
8x + 4x + -12 = 24x + 16 + -4
(8x) + (4x) +(-12) = (24x) + (16 + -4) (combine like terms)
12x + -12 = 24x + 12
12x -12 = 24x + 12
Step 2: Subtract 24x from both sides.
12x -12 -24x = 24x + 12 -24x
-12x -12 = 12
Step 3: Add 12 to both sides.
-12x - 12 + 12 = 12 + 12
-12x = 24
Step 4: Divide both sides by -12.
-12x/-12 = 24/-12 <u>x = -2</u>
HOPE THIS HELPED!!!
Answer:
Find the LCM of 3.5 and 2.25
Step-by-step explanation:
which is 31.5
Answer:
The answer would be -x/3x^6
Step-by-step explanation:
The first step that you should take is apply the fraction rule.
That would make it -1/3/x^6
Then apply the fraction rule again.
That would make it. 1/3/-x^6
Then apply the last fraction rule.
That would make it -1/3x^6
