step 1
<u>Find the number of miles run by each bus in one day</u>
we know that
speed=distance/time
distance=speed*time
distance=(15 mi/h)*3 h=45 miles
<u>Find the number of miles run by the total buses in one day</u>
Multiply by 300
300*45=13,500 miles
<u>Find the number of miles run by the total buses in 22 days</u>
13,500*22=297,000 miles
step 2
<u>Find the number of gallons to run 297,000 miles</u>
we know that
the fuel economy of the buses is 10 mi/gal
so
by proportion

step 3
<u>Find the cost of 29,700 gal of gasoline</u>
we know that
the gasoline costs $4.10 per gallon
then
29,700*4.10=$121,770
therefore
<u>the answer is</u>
the cost of the gasoline is $121,770
Answer:
3. Yes, because 160 / 4 = 40 and 120 / 3 = 40.
4. 10, because 24 / 12 = 2 and 20 / 2 = 10
SOLUTION:
Case: Hypothesis testing
Step 1: Null and Alternative hypotheses

Step 2: T-test analysis

Step 3: t-test with the significance level

Step 4: Comparing

So tail to reject the null hypothesis. There is enough evidence at a 0.05 level of significance to claim that the mean spent is greater than P127.50.
Final answer:
Yes, there is evidence sufficient to conclude that the mean amount spent is greater than P127.50 per month at a 0.05 level of significance.
Answer: 62.83in
Step-by-step explanation:
C= 2(3.14)(10)
C= 20(3.14)
C= 62.831853071796