Question

A large school district has 300 buses. if each school bus is used 3.0 hours each day, the average speed of the school buses is 15 mi/h, and the fuel economy of the buses is 10 mi/gal. how much does it cost to run theses buses for 22 school days if gasoline costs $4.10 a gallon

Answer 1

step 1

Find the number of miles run by each bus in one day

we know that

speed=distance/time

distance=speed*time

distance=(15 mi/h)*3 h=45 miles

Find the number of miles run by the total buses in one day

Multiply by 300

300*45=13,500 miles

Find the number of miles run by the total buses in 22 days

13,500*22=297,000 miles

step 2

Find the number of gallons to run 297,000 miles

we know that

the fuel economy of the buses is 10 mi/gal

so

by proportion

$\frac{10}{1} \frac{miles}{gal}= \frac{297,000}{x} \frac{miles}{gal} \\ \\10*x=297,000 \\ \\x=29,700\ gal$

step 3

Find the cost of 29,700 gal of gasoline

we know that

the gasoline costs $4.10 per gallon

then

29,700*4.10=$121,770

therefore

the answer is

the cost of the gasoline is $121,770