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Zanzabum
3 years ago
8

Ill give brainliest - please help ASAP WITH THE WORK THO PLEASE?

Mathematics
1 answer:
evablogger [386]3 years ago
5 0

Answer:

this is your answer look it once

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Find the radius of a circle with an area of 16x^2+24x+9
Diano4ka-milaya [45]
Area of circle =π *r^2
so π*r^2 = π(16x^2 + 24x + 9)
r^2 = 16x^2 + 24x + 9
= (4x +3)(4x+3)
= (4x +3)^2
Take square roots of both sides
r = 4x +3
8 0
3 years ago
Determine which values of p the following integrals converge. Give your answer in each case by selecting the appropriate inequal
sashaice [31]

Answer:

Step-by-step explanation:

a)

\int\limits^2_1 {\frac{1}{x(lnx)^p} } \, dx

this can be done by substitute lnx = u

dx/x = du

When x =1, u =0 and when x =2, u = ln 2

So integral = \int\limits^{ln2} _0 {du/u^p} \\\=\frac{u^{-p+1} }{-p+1}

We find that this integral value is not definid for p =1

Hence for values of p other than 1, this converges.

When we substitute limits

\frac{1}{1-p} ((ln2)^{1-p} -1)

and converges for p ≠1

b) \int\limits^1_0 {lnx}/x^p \, dx \\\int \frac{\ln \left(x\right)}{x^p}dx=\frac{1}{-p+1}x^{-p+1}\ln \left(x\right)-\frac{x^{-p+1}}{\left(-p+1\right)^2}+C

So not converging for p =1

But ln x is defined only for x >0

So integral 0 to 1 makes this integral not valid and hence not convergent.

7 0
4 years ago
Adam can paint 38 feet of fence per hour. How many yards of fence can he paint per hour? 12 yards per hour 456 yards per hour 11
Romashka-Z-Leto [24]

Answer:

12.66 yards/hour

Step-by-step explanation:

38 feet/3 feet per yard=12.66 yards

6 0
3 years ago
Read 2 more answers
Lin runs 12 laps around a track in 15 minutes.
nalin [4]

Answer:

1.25

Step-by-step explanation:

15/12

5 0
4 years ago
Which equation matches the graph shown below?
MrRa [10]
Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:

y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5

To try to discard one of them, let us use the vertex, which is at x = -2.

With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.

Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.

Then, the answer is 2x^2 + 8x  -5
8 0
4 years ago
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