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zloy xaker [14]
2 years ago
11

Center: (2,8), Radius: 3

Mathematics
1 answer:
Rzqust [24]2 years ago
5 0

Answer:

I’m not sure what this question is asking, but I’ll write an equation of this circle you are describing. Here, the x coordinate of the center is h, the y coordinate is k, and radius is r in the equation : (x-h)^2+(y-k)^2=r^2, meaning the equation in this situation is the following: (x-2)^2+(y-8)^2=9

Step-by-step explanation:

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e-lub [12.9K]

Answer:

-8<x<2


Step-by-step explanation:


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If a school policy maker wanted to learn what expectations must be met to receive funding from H.R.5, what titles would that per
lukranit [14]
I'm definite about a b c
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3 years ago
A scale on a blue print drawing of a house shows that 10 1010 centimeters represents 2 22 meters. What number of actual meters a
Ivenika [448]

Answer:

On Blue print 18 centimeters represents <u>3.6 meters</u>.

Step-by-step explanation:

Given:

Scale is 10 cm = 2 m

We need to find the number of actual meters are represented by 18 1818 centimeters on the blue print.

Solution:

Now we know that;

10 cm = 2 m

so 1 cm = Number of meters in 1 cm.

By using Unitary method we get;

Number of meters in 1 cm = \frac{2}{10}=0.2\ m

Now we know that;

1 cm = 0.2 m

18 cm = Number of meters in 18 cm.

Again by using Unitary method we get;

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Hence On Blue print 18 centimeters represents <u>3.6 meters</u>.

7 0
2 years ago
Do many fishermen collect worms at night?
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The question actually relates to finding the direct object in the sentences given.
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In the second sentence, the direct object is "worms". <span>The correct option among all the options that are given in the question is the first option or option "A".

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6 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
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