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3 years ago

Can you please help me

Mathematics

1 answer:

Andrej [43]3 years ago

7 0

Step-by-step explanation:

CBD is a inscribed angle of Arc CBA so

$5x = \frac{8x + 48}{2}$

$5x = 4x + 24$

$x = 24$

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Determine whether the two expressions are equivalent. If so, tell what property is applied. If not, explain why. 10 ÷ 5 and 5 ÷

nikklg [1K]

Answer:

no, its not equivalent

Step-by-step explanation:

10/5= 2

5/10=0.5

5 0

3 years ago

Paul could play 16 songs. He learns some new songs. Now, Paul can play 23 songs. In the first box, enter an equation to represen

Murrr4er [49]

16 + s = 23

-16 =-16

s= 7

8 0

3 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

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Kelly used 3 2/9 packs of notebook paper in the first 1/6 of the year. At what rate is Kelly using notebook paper.

Makovka662 [10]

Answer:

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4 0

3 years ago

Out of 30 students are surveyed 17 have a dog based on these results predict how many of the 300 students in the school have a d

zubka84 [21]

$From\ proportion:\\
30\ students\ 17\ dogs\\
300\ students\ x\ dogs\\\\Cross\ multiplication\\
30x=300*17\\
30x=5100\ \ \ | divide\ by\ 30\\
x=170\\\\
There\ will\ be\ 170\ dogs\ for\ 300\ students.$

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3 years ago

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