The advance tickets were 35 in number and the same day ticket will be 30 in number.
<h3>What will be the number of tickets?</h3>
To find out the number of the tickets sold we will give some notations so the notations are as follows:-
A= Cost of advance tickets=$30
S= cost of same-day ticket-=15
Number of the advance tickets
Number of same-day tickets.
The equations made by the given data will be:-
By solving the above equations:-
Hence the advance tickets were 35 in number and the same day ticket will be 30 in number.
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Answer:
345%
Step-by-step explanation:
Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
F(2)=8 and f(5v)=25v^2+15v-2
