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3 years ago

I NEED HELP ASAP!!!

Mathematics

2 answers:

seraphim [82]3 years ago

8 0

Answer:

SVU = 90

TUV = 65

Step-by-step explanation:

harina [27]3 years ago

6 0

Answer:

sorry if it's messy, I tried my best even though I'm not sure for ST.

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Does water have a taste

MariettaO [177]

Answer:

nope

Step-by-step explanation:

Water is tasteless and odorless

6 0

3 years ago

Read 2 more answers

The rectangular walkway will be 3 feet wide and 18 feet long. each 2-foot by 3-foot stone covers an area of 6 square feet. how m

anygoal [31]

3x18=54sq ft
2x3=6sq ft
54/6=9 stones needed

7 0

4 years ago

The value of the square root of 82 is between which two integers?

zaharov [31]

The answer: 9 and 10 or 8 and 9
8x8=64
9x9=81
10x10=100
They are close by 18 so If it’s only an answer I would go for 8 and 9

8 0

4 years ago

Please answer this question

Tems11 [23]

$\bold{\huge{\underline{ Solution }}}$

<h3>Given :- </h3>

• $\sf{ Polynomial :- ax^{2} + bx + c }$

• The zeroes of the given polynomial are α and β .

<h3>Let's Begin :- </h3>

Here, we have polynomial

$\sf{ = ax^{2} + bx + c }$

We know that, 

Sum of the zeroes of the quadratic polynomial

$\sf{ {\alpha} + {\beta} = {\dfrac{-b}{a}}}$

And 

Product of zeroes

$\sf{ {\alpha}{\beta} = {\dfrac{c}{a}}}$

Now, we have to find the polynomials having zeroes :-

$\sf{ {\dfrac{{\alpha} + 1 }{{\beta}}} ,{\dfrac{{\beta} + 1 }{{\alpha}}}}$

Therefore ,

Sum of the zeroes

$\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} )+( {\beta}+{\dfrac{1 }{{\alpha}}})}$

$\sf{ ( {\alpha} + {\beta}) + ( {\dfrac{1}{{\beta}}} +{\dfrac{1 }{{\alpha}}})}$

$\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{{\alpha}+{\beta}}{{\alpha}{\beta}}}}$

$\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{-b/a}{c/a}}}$

$\sf{ {\dfrac{ -b}{a}} + {\dfrac{-b}{c}}}$

$\bold{{\dfrac{ -bc - ab}{ac}}}$

Thus, The sum of the zeroes of the quadratic polynomial are -bc - ab/ac

Product of zeroes

$\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} ){\times}( {\beta}+{\dfrac{1 }{{\alpha}}})}$

$\sf{ {\alpha}{\beta} + 1 + 1 + {\dfrac{1}{{\alpha}{\beta}}}}$

$\sf{ {\alpha}{\beta} + 2 + {\dfrac{1}{{\alpha}{\beta}}}}$

$\bold{ {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}$

Hence, The product of the zeroes are c/a + a/c + 2 .

We know that, 

For any quadratic equation

$\sf{ x^{2} + ( sum\: of \:zeroes )x + product\:of\: zeroes }$

$\bold{ x^{2} + ( {\dfrac{ -bc - ab}{ac}} )x + {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}$

Hence, The polynomial is x² + (-bc-ab/c)x + c/a + a/c + 2 .

<h3>Some basic information :-</h3>

• Polynomial is algebraic expression which contains coffiecients are variables.

• There are different types of polynomial like linear polynomial , quadratic polynomial , cubic polynomial etc.

• Quadratic polynomials are those polynomials which having highest power of degree as 2 .

• The general form of quadratic equation is ax² + bx + c.

• The quadratic equation can be solved by factorization method, quadratic formula or completing square method.

6 0

2 years ago

Find the surface area of the prism? HELP I need the steps if possible

Helga [31]

To find the surface area of a figure, find the area of all the shapes that make up the figure to get the area multiply Base by the height. First let's find the area of the rectangle and the front that makes the ramp. To do this multiply 20 by 17 to get 340. Then let's get the area of the rectangle on the bottom by multiplying 15 by 20 to get 300. Now lets find the area of the rectangle in the back we will do this by multiplying 8 by 20 get 160. To get the area of a triangle multiply the base by the height and then divided by 2. so for one of the triangles let's multiply A perfect in which gives us 120 and divide that by 2 to get 60. because the other triangle has the same dimensions, the area of the other triangle will also be 60. now let's out of all the areas that we have from the shapes which will be 340 + 300 + 160 + 60 + 60 which will give us 920 so the area of the figure is 920ft^2

(can i get brainelist pls)

5 0

3 years ago