The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.
Since the plane passes through point (-5,9,10), the required plane is :
Π 1(x-(-5)+4(y-9)-3(z-10)=0
=>
Π x+4y-3z=1
Answer:
480 cm ^ 2
Step-by-step explanation:
To calculate the surface area of the figure, we must calculate the surface area of the cube, we know that they are identical, therefore, calculating the area of one is sufficient.
We have that the surface area of a cube is:
A = 6 * a ^ 2
where a is the edge, we know that if it is a cube all its sides are equal, in this case it is 4 centimeters, if we replace we have:
A = 6 * (4 ^ 2)
A = 96
96 square centimeters is the area of a cube, but since the area of the object would be the sum of the area of all the cubes, then:
AT = 96 * 5
AT = 480 cm ^ 2
The surface area of the object formed with the cubes is 480 cm ^ 2
Answer: It would be B
Step-by-step explanation:
;)
Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
