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3 years ago

7/12-1/3= plz help me

Mathematics

2 answers:

Leto [7]3 years ago

7 0

Answer:

0.25

Step-by-step explanation:

Serhud [2]3 years ago

7 0

Answer:

1/4

Step-by-step explanation

least common denominator is 12 so 7-4/12

7 - 4 = 3

3/12

simplified = 1/4

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$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

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The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

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The F-test statistics value is :

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$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

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The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

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7/12-1/3= plz help me​

7/12-1/3= plz help me