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3 years ago

Find the Value of x.

Mathematics

1 answer:

svlad2 [7]3 years ago

8 0

I got 83! hope this helps

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What number is 35% of 22

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3 years ago

Read 2 more answers

6x-4bracket(2x-5)>8 or 5x+9<2x-21

Yuri [45]

The solutions to the given inequalities are x < 6 OR x < -10

<h3>Linear Inequalities </h3>

From the question, we are to solve the given inequalities

The given inequalities are

6x - 4(2x - 5) > 8 or 5x + 9 < 2x - 21

First solve,

6x - 4(2x - 5) > 8

Clear the bracket

6x -8x + 20 > 8

6x - 8x > 8 - 20

-2x > -12

Divide both sides by -2 and flip the sign,

That is,

-2x/-2 > -12/-2

x < 6

For,

5x + 9 < 2x - 21

Subtract 2x from both sides

5x - 2x + 9 < 2x - 2x -21

3x < -21 -9

3x < -30

Divide both sides by 3

3x/3 < -30/3

x < -10

Hence, the solutions to the given inequalities are x < 6 OR x < -10

Learn more on Inequalities here: brainly.com/question/246993

#SPJ1

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1 year ago

There are three monomials such that the greatest common factor of the first and second monomial is 2xy and the greatest common f

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Hi, I'm an employer of Brainly. Someone will answer you in the next 10 minutes. Thank you for your patience! Have a great day.

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3 years ago

Find the particular solution that satisfies the differential equation and the initial condition.

Vesnalui [34]

Answer:

1) $y =4x^2 +7$

2) $y =7s^2 -3s^4 +181$

Step-by-step explanation:

Assuming that our function is $y = f(x)$ for the first case and $y=f(s)$ for the second case.

Part 1

We can rewrite the expression like this:

$\frac{dy}{dx} =8x$

And we can reorder the terms like this:

$dy = 8 x dx$

Now if we apply integral in both sides we got:

$\int dy = 8 \int x dx$

And after do the integrals we got:

$y = 4x^2 +c$

Now we can use the initial condition $y(0) =7$

$7 = 4(0)^2 +c, c=7$

And the final solution would be:

$y =4x^2 +7$

Part 2

We can rewrite the expression like this:

$\frac{dy}{ds} =14s -12s^3$

And we can reorder the terms like this:

$dy = 14s -12s^3 dx$

Now if we apply integral in both sides we got:

$\int dy = \int 14s -12s^3 ds$

And after do the integrals we got:

$y = 7s^2 -3s^4 +c$

Now we can use the initial condition $y(3) =1$

$1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181$

And the final solution would be:

$y =7s^2 -3s^4 +181$

7 0

3 years ago