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yawa3891 [41]
2 years ago
15

A company that makes cola drinks states that the mean caffeine content per 12-ounce bottle of cola 40 milligrams. You want to te

st this claim. During your tests, you find that a random sample of thirty 12-ounce bottles of cola has a mean caffeine content of 39.2 milligrams. Assume the population is normally distributed with a standard deviation of 7.5 milligrams. At α=0.01, can you reject the company’s claim
Mathematics
1 answer:
Ad libitum [116K]2 years ago
8 0

Answer:

Claim cannot be rejected

Step-by-step explanation:

We solve this by using hypothesis testing

H0: mean = 40

H1: mean ≠ 40

We have samples of 30, but we were not gives the population standard deviation. We used the t distribution

T score = 39.2-40/(7.5/√30)

= -0.5842

Degree of freedom = 30-1 = 29

Then p value = 0.5636

In conclusion, we fail to reject the null hypothesis since 0.5636 > 0.01 significance level.

So company's claim cannot be rejected

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-12x - 12y = 4 3x + 3y = 0
Svetradugi [14.3K]

Answer:

no Solution

Step-by-step explanation:

-12x-12y=4\\ 3x+3y=0

12x-12y=4

add 12y to both sides

12x-12y+12y=4+12y

divid both sides by -12

\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}

simplfy

x=-\frac{1+3y}{3}

\mathrm{Substitute\:}x=-\frac{1+3y}{3}

\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}

\begin{bmatrix}-1=0\end{bmatrix}

7 0
3 years ago
How do you do these questions?
Tanzania [10]

Answer:

μ ≈ 2.33

σ ≈ 1.25

Step-by-step explanation:

Each person has equal probability of ⅓.

\left[\begin{array}{cc}X&P(X)\\1&\frac{1}{3}\\2&\frac{1}{3}\\4&\frac{1}{3}\end{array}\right]

The mean is the expected value:

μ = E(X) = ∑ X P(X)

μ = (1) (⅓) + (2) (⅓) + (4) (⅓)

μ = ⁷/₃

The standard deviation is:

σ² = ∑ (X−μ)² P(X)

σ² = (1 − ⁷/₃)² (⅓) + (2 − ⁷/₃)² (⅓) + (4 − ⁷/₃)² (⅓)

σ² = ¹⁴/₉

σ ≈ 1.25

3 0
3 years ago
Tan^2x+sec^2x=1 for all values of x. <br> true or false?
amid [387]

This is not true.

\tan^2x+\sec^2x=\dfrac{\sin^2x}{\cos^2x}+\dfrac1{\cos^2x}=\dfrac{1-\cos^2x+1}{\cos^2x}=2\sec^2x-1

2\sec^2x-1=1\implies\sec^2x=1\implies\sec x=\pm1\implies x=n\pi

where is n is any integer. So suppose we pick some value of x other than these, say x=\dfrac\pi4. Then

\tan^2\dfrac\pi4+\sec^2\dfrac\pi4=1+2=3\neq1

5 0
3 years ago
Read 2 more answers
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Aleonysh [2.5K]

Answer:

C)265

Step-by-step explanation:

To find the median you list all the numbers in order from least to greatest. The number in the middle is the median.

In this case there are two middle number so you have to add them together then devide them by 2.

700, 740, <u>810, 900</u>, 1050, 1120.

810 + 900 = 1,710

1,710/2 = 855.

Your median is 855.

To find the difference you just subtract the two numbers.

1,120-855= 265.

7 0
2 years ago
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52 \frac{11}{40}

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