Since he must not exceed 8 hours driving in a day:
Let the distance of the picnic be = x km.
Therefore time for forward journey = x / 60
Return journey = x / 50
The total trip should not exceed 8 hours.
Therefore: x / 60 + x / 50 <= 8. LCM = 300
Taking LCM and multiplying on both sides:
5x + 6x <= 8(300)
11x <= 2400
x <= 2400/11
x <= 218.18
The picnic spot must be less than or equal to 218.18 km.
Hello,
mes angle AEC=(69+105)/2=87
mes angle AED=(74+112)/2=93
Answer A
S= R- 1/3R
The first problem s=18 r-= 6
This is how it works
Use S-= R-1/3R
12= 18-1/3(18)
12= 18-6
12=12
We need the square and the lengths of it to help you
f(x) = 5x is linear. Just a straight line with a slope of +5. So if the intervals are both a difference of 1, then the average rate of change will be the same.
f(x2) - f(x1) over x2 - x1. That's the formula for average rate of change.
So for Section A:
f(x) = 5x, (0,1)
[f(1) - f(0)]/(1-0)
= [5(1) - 5(0)]/1
=(5)/1
=5
Do the same for section B and you'll get 5 as well.
I hope this helps you because I have no clue if my answer is right
