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allsm [11]
3 years ago
11

One week, Gabriel bought 2 bags of beans and 3 bags of rice. The next week, he bought 4 bags of beans and 1 bag of rice. Let b r

epresent the cost of each bag of beans and r represent the cost of each bag of rice. Simplify the expression for the total cost, shown below.
(2b + 3r) + (4b+ r)
Mathematics
1 answer:
mojhsa [17]3 years ago
4 0
( 2b + 3r ) + ( 4b + r )
= 6b + 4r
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The measure of angle W is...?
bekas [8.4K]

Y = 180° - 52° = 128°

W + X + Y = 180°

\tt (4y-4) + 3y + 128^o=180^o\\\\7y+124^o=180^o\\\\7y=56\rightarrow y=8\\\\W=4(8)-4=28^o

5 0
2 years ago
Solve and check <br> 2/3y =6 <br> A.1/9 <br> B.1/4<br> C.9<br> D.4
kotegsom [21]
\frac{2}{3}y=6\ \ \ \ |divide\ both\ sides\ by\ \frac{2}{3}\ /multiply\ by\ \frac{3}{2}/\\\\y=6\cdot\frac{3}{2}\\\\y=\frac{6}{1}\cdot\frac{3}{2}\\\\y=\frac{\not6^3\cdot3}{1\cdot\not2_1}\\\\y=\frac{3\cdot3}{1\cdot1}\\\\y=\frac{9}{1}\\\\\boxed{y=9}\leftarrow answer\ \boxed{C}

check:\\\\/put\ the\ value\ of\ y=9\ to\ the\ equation\ \frac{2}{3}y=6/\\\\\frac{2}{3}\cdot9=6\\\\\frac{2}{3}\cdot\frac{9}{1}=6\\\\\frac{2}{\not3_1}\cdot\frac{\not9^3}{1}=6\\\\\frac{2}{1}\cdot\frac{3}{1}=6\\\\2\cdot3=6\\\\\boxed{6=6}\leftarrow TRUE


8 0
4 years ago
Read 2 more answers
Yolanda buys two types of flowering plants. She buys 36 geraniums and 63 marigolds. She wants to plant an equal number of flower
a_sh-v [17]

Answer:

The answer is 9

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Josie took a long multiple-choice, end-of-year vocabulary test. The ratio of the number of problems Josie got incorrect to the n
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2*_=16

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2*8=16

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Therefore Josie got 72 answers correct
7 0
3 years ago
Consider the following sample set of scores. Assume these scores are from a discrete distribution. 21 29 32 38 38 45 50 64 72 10
ASHA 777 [7]

Answer:

Original data: 21 29 32 38 38 45 50 64 72 100

\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9

Mode =38.

Median = \frac{38+45}{2}=41.5

Change 1: 2 29 32 38 38 45 50 64 72 100

\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47

Mode =38.

Median = \frac{38+45}{2}=41.5

Change 2: 29 32 38 38 45 50 64 72 100

\bar X = \frac{29+32+38+38+45+50+64+72+100}{9}=52

Mode =38.

Median = 45

Step-by-step explanation:

Original data: 21 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{10} X_i}{10}

And if we replace we got:

\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

Median = \frac{38+45}{2}=41.5

Change 1: 2 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{10} X_i}{10}

And if we replace we got:

\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

Median = \frac{38+45}{2}=41.5

Change 2: 29 32 38 38 45 50 64 72 100

Now the sample size is 9 instead of 10

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{9} X_i}{9}

And if we replace we got:

\bar X = \frac{29+32+38+38+45+50+64+72+100}{9}=52

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have odd number of points the median is calculated from the 5 position of the dataset ordered.

Median = 45

7 0
4 years ago
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