The solution to the Questions are
- The alternate hypothesis demonstrates that there are two possible outcomes for the test.
- Decision rule: If z > 2.05 or z<-2.05, reject H0
- The two-tailed nature of the test is shown by the alternative hypothesis.
- The result of the test yields the following P-value: 0.0096
<h3>What is the alternate hypothesis?</h3>
(a)
The alternate hypothesis demonstrates that there are two possible outcomes for the test.
(b)
Here we have
(b)
Here the test is two-tailed. So for 
, the critical values of the z-test are -2.05 and 2.05.
Decision rule: If z > 2.05 or z<-2.05, reject H0
(c)
Test statistics will be
z=2.59
(d)
The two-tailed nature of the test is shown by the alternative hypothesis.
(e)
The result of the test yields the following P-value: 0.0096
Read more about P-value
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<u>Given</u>:
Given that the radius of the figure is 6 units.
We need to determine the area of the shape.
<u>Angle of the shape:</u>
The angle of the shape is given by
Hence, the angle of the shape is 270°
<u>Area of the shape:</u>
The area of the shape can be determined using the formula,
Substituting r = 6, we get;
Simplifying, we get;
Thus, the area of the shape is 84.78 square units.
Answer:
2079
Step-by-step explanation:
Homes without children outnumbers homes with children by about 7 to 5 ;
If number of children = 3564
Number of homes without children :
Expressing the relaship interms of ratio :
Without children : with children = 7 :5
Total ratio = 7 + 5 = 12
Number of homes without children:
(7 / 12) * 3564
0.5833333 * 3564
= 2079
Answer:
of oil.
Step-by-step explanation:
Firstly, you need to find the LCD (lowest common denominator), this can be done by factoring the denominators and knowing the multiples.
In this case, you can see that 2 is a factor of 8 so we can simply multiply 
so that the denominator is 8:
8 ÷ 2 = 4
Now the fractions can be added easily:
= of oil.
Hope this helps!
First we see that we can factor out a 5 from everybody
5(-a^2+2ab^2-4+5ba^3)
trial and eror and experience
order in poawer order
5(5a^3b-a^2+2ab^2-4)
5(a^2(5ab-1)+2(ab^2-2))
dunno how to go on further
