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3 years ago

I could really use your help:)

Mathematics

1 answer:

Colt1911 [192]3 years ago

3 0

Answer:

Question 1: -3 and 6 in that order

Question 3: 3 and y=1/2x+3 in that order

Question 2: 2 and y=2x+4 in that order

Step-by-step explanation:

You might be interested in

Help me please!! If you do you will get 25 points :)

Radda [10]

Answer:

24 units by 15 units

Step-by-step explanation: To find how many units the length and width are, divide each by 5:

120/5 = 24

75/5= 15

For every 5 feet, there is 1 unit .

6 0

3 years ago

How do you factor 125-x^3?

xz_007 [3.2K]

Step-by-step explanation:

We have

$125 - x {}^{3}$

First, 125 is a perfect cube because

$5 \times 5 \times 5 = 125$

and

x^3 is a perfect cube because

$x \times x \times x = x {}^{3}$

so we can use the difference of cubes identity

$( {x}^{3} - {y}^{3} ) = (x - y)( {x}^{2} + xy + {y}^{2} )$

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

$64 - 27$

we know that

$64 - 27 = 37$

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

$(4 - 3)( {4}^{2} + 4(3) + 3 {}^{2} )$

$1(16 + 12 + 9) = 1(37) = 37$

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

$(5 - x)( {5}^{2} + 5x + {x}^{2} ) =$

$(5 - x)(25 + 5x + {x}^{2} )$

3 0

2 years ago

Read 2 more answers

Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

6 0

3 years ago

- What is the range of the following set of points: {(3, 4), (7, - 2), (11, – 8)}?

konstantin123 [22]

Answer:

B) {-8,-2,3,4,7,11}

Step-by-step explanation:

range is y

3 0

3 years ago

I need help pleessse

wariber [46]

Answer:

1. 8/3

2. 1/7

3. 1/12

4. 1/27

Step-by-step explanation:

1. 3/8 * m = 1

Multiply by 8/3

8/3 * 3/8 m = 1* 8/3

m = 8/3

2. 7 * m = 1

Divide by 7

7*m /7 = 1/7

m = 1/7

3. 3 ÷m = 36

Multiply by m

3 ÷m * m = 36*m

3 = 36*m

Divide by 36

3/36 = 36*m/26

1/12 = m

4. 4/9 ÷m = 12

Multiply by m

4/9 ÷m * m = 12*m

4/9 = 12*m

Multiply by 1/12

4/9 *1/12 = 12*m * 1/12

4/12 *1/9 = m

1/3*1/9 =m

1/27

4 0

3 years ago