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Sergeeva-Olga [200]
3 years ago
6

I could really use your help:)

Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0

Answer:

Question 1: -3 and 6 in that order

Question 3: 3 and y=1/2x+3 in that order

Question 2: 2 and y=2x+4 in that order

Step-by-step explanation:

:)

You might be interested in
Help me please!! If you do you will get 25 points :)
Radda [10]

Answer:

24 units by 15 units

Step-by-step explanation: To find how many units the length and width are, divide each by 5:

120/5 = 24

75/5= 15

For every 5 feet, there is 1 unit .

6 0
3 years ago
How do you factor 125-x^3?
xz_007 [3.2K]

Step-by-step explanation:

We have

125 - x {}^{3}

First, 125 is a perfect cube because

5 \times 5 \times 5 = 125

and

x^3 is a perfect cube because

x \times  x \times x = x {}^{3}

so we can use the difference of cubes identity

( {x}^{3}  -  {y}^{3} ) = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

64 - 27

we know that

64 - 27 = 37

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

(4 - 3)( {4}^{2}  + 4(3) + 3 {}^{2} )

1(16 + 12 + 9) = 1(37) = 37

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

(5 - x)( {5}^{2}  + 5x +  {x}^{2} ) =

(5 - x)(25 + 5x +  {x}^{2} )

3 0
2 years ago
Read 2 more answers
Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers
slamgirl [31]

Answer:

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

Step-by-step explanation:

Let be \vec u = (2,-3), its unit vector is determined by following expression:

\hat {u} = \frac{\vec u}{\|\vec u \|}

Where \|\vec u \| is the norm of \vec u, which is found by Pythagorean Theorem:

\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}

\|\vec u\| = \sqrt{13}

Then, the unit vector is:

\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)

\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right)

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

6 0
3 years ago
- What is the range of the following set of points: {(3, 4), (7, - 2), (11, – 8)}?
konstantin123 [22]

Answer:

B) {-8,-2,3,4,7,11}

Step-by-step explanation:

range is y

3 0
3 years ago
I need help pleessse
wariber [46]

Answer:

1.  8/3

2.   1/7

3.  1/12

4.  1/27

Step-by-step explanation:

1.  3/8 * m = 1

Multiply by 8/3

8/3 * 3/8 m = 1* 8/3

m = 8/3


2.  7 * m = 1

Divide by 7

7*m /7 = 1/7

m = 1/7


3.  3 ÷m = 36

Multiply by m

3 ÷m * m = 36*m

3 = 36*m

Divide by 36

3/36 = 36*m/26

1/12 = m


4.  4/9 ÷m = 12

Multiply by m

4/9 ÷m * m = 12*m

4/9 = 12*m

Multiply by 1/12

4/9 *1/12 = 12*m * 1/12

4/12 *1/9 = m

1/3*1/9 =m

1/27

4 0
3 years ago
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