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MAXImum [283]
3 years ago
15

Plzzzzzzz helpppppppp

Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0

Answer:

-5x^2+125

Step-by-step explanation:

You need to go step-by-step here. I would actually prefer to multiply by 5 at the end, because it's easier that way. (You can multiply the terms in any order you want, though.)

So first, multiply (5-x)(5+x). This is a special product: (a-b)(a+b)=a^2-b^2, so:

(5-x)(5+x)=5^2-x^2=25-x^2

But even if you don't know that special product, you can multiply it out. Rewrite (5-x)(5+x) as 5(5+x)-x(5+x).

 5(5+x)-x(5+x)

=25+5x-(5x+x^2)

=25+5x-5x-x^2

=25+0x-x^2

=25-x^2

As you can see, the result is the same regardless of you get it. Now multiply that by 5 to get 125-5x^2, or in standard form, -5x^2+125.

Hope I could help you!

Zigmanuir [339]3 years ago
3 0

Answer:

125-5x^2

this is the answer

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PLEASE SOMEONE HELP I TRULY DO NOT UNDERSTAND
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Hi there!

\large\boxed{f^{-1}(x) =  \sqrt[3]{\frac{x+4}{9} } }

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x = 9y^{3} - 4

Isolate y by adding 4 to both sides:

x + 4 = 9y^{3}

Divide both sides by 9:

\frac{x+4}{9}= y^{3}

Take the cube root of both sides:

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| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the
Westkost [7]

Answer:

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

          <u>Left</u>      <u>Speed(km/h)</u>      <u>Time</u>

Car:   12PM            X  

Van:   12PM           60

Car/Van

DistanceCar        AB + z

DistanceVan       Az

Ratio:                  (AB+z)/Az  = 7/5

Time until both meet = T (in hours)

Distance Car:            xT

Distance Van:           60T

====

  xT = AB + z

  60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is:    time (hr) = 108 km/(84 km/h)

                                                 time = 1.286 hours

Distance for at 1.289 hours is:    distance (km) = (60 km/h)*(1.286 h)

                                                   distance = 77.14 km

At 1.286 hours, the car reverses direction.  The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours.  The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let <u>t</u> be the time <u>after</u> 1.286 hours that both vehicles meet/collide.

t*(60 km/h)  +  t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

==============

<u>CHECK</u>

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

<u><em>YES</em></u>

     

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Answer:

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Step-by-step explanation:

In this question, from the data given, we want to calculate the probability that an adult selected at random has liver problems.

Let E(L) be the event that an adult has liver problems.

The probability is directly obtainable from the question and it is given as 8%

Thus, the probability that the selected adult has liver problems; P(L) = 8% = 8/100 = 0.08

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