<h3>
Answer: C) 4</h3>
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Work Shown:
Expand out the left hand side
(x-k)(x-5)
x(x-5)-k(x-5)
x^2-5x-kx+5k
Note that the constant term here is 5k. Yes k seems like a variable, but it's actually a constant. Once we know k, we can replace it to get a fixed number. In this case, k = 4 since 5k = 5*4 = 20 to have it match with the 20 at the end of x^2-9x+20
For the x terms, we have -5x-kx = -5x-4x = -9x which matches with the middle term of x^2-9x+20
Therefore,
(x-k)(x-5) = x^2-9x+20
updates to
(x-4)(x-5) = x^2-9x+20
The -4 and -5 multiply to 20, and they also add to -9. This helps confirm we have the right k value.
Answer:
A just sub y of first equation into second then solve for X value
Hi
i have just tried this equation just now.
tell me if i made some mistakes please
S=1.68-0-0+2x
A=1.68+2x
Answer:
See below
Step-by-step explanation:
(1) 2x + 3y = 15
(2) x - 3y = 3
First step:
Add Equations (1) and (2).
Reason:
The y terms have the same coefficient (3). If I add +3 and -3, the two terms will cancel each other (be eliminated).
How it helps:
If I eliminate the y terms, I have only one variable, the x variable, to deal with.
(1) 2x + 3y = 15
(2) x - 3y = 3
(3) 3x = 18
I can then easily solve Equation (3) for the value of x.
Download the app slander and you might be able to find the answers and the textbook there
