Answer:
Therefore, the value of K_{p} is 2 \times 10^{9} and value of \Delta G^{o} is -53.2 kJ/mol.
Explanation:
The cool thing about chemical equations is that the mole ratios between compounds is the same as the ratios shown in the balanced equation.
So first, check to make sure the equation is balanced. I just looked at it, and it is (if you can't tell, that means there're the same number of each kind of atom on both sides of the equation).
The answer lies in the coefficients.
So, you'll notice there's a 3 in front of the sodium hydroxide and no coefficient (which implies 1) in front of the iron trichloride.
It's literally that simple: 3:1.
The answer is D.
The given question is incomplete. The complete question is :
What volume of 0.160 M solution of KOH must be added to 550.0 mL of the acidic solution to completely neutralize all of the 0.150 M hydrochloric acid?
Answer: Volume in liters to three significant figures is 0.516 L
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH
We are given:
Putting values in above equation, we get:
(1L=1000ml)
Thus volume in liters to three significant figures is 0.516 L
Answer:
0.19M
Explanation:
2A → A2
Rate constant = 0.0265 M–1min–1
Initial concentration = 2.00 M
Final Concentration = ?
time, t = 180min
The formular relating the parameters is given as;
1 / [A] = kt + 1 / [A]o
1 / [A] = 0.0265 * 180 + (1 / 2)
1 / [A] = 4.77 + 0.5
[A] = 1 / 5.27 = 0.19M
