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3 years ago

What is the ph of a solution containing the strong base ba(oh)2 at a concentration of 0.064 mol/l?

1 answer:

3 0

The pH of a solution is a measure used to evaluate the acidity of a solution. It is related to the hydronium ion concentration in the solution. It is expressed as pH = -log [H+]. Also, it is related to pOH by the equation 14 = pH + pOH. It is stated that the substance given in the problem is a strong base which means that it completely dissociates into ions. It dissociates as follows:

Ba(OH)2 = Ba^2+ + 2OH-

To determine the pH of the solution, we need to determine the OH- concentration. Then, find pOH. We do as follows:

[OH-] = 0.0064 mol Ba(OH)2 / L ( 2 mol OH- / 1 mol Ba(OH)2 ) = 0.0128 mol OH- / L

pOH = -log (0.0128) = 1.8928
pH = 14 - 1.8928 = 12.1072

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Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

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The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

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$N_2$ $7.81\times 10^{-1}$ $6.70\times 10^{-4}$

$O_2$ $2.10\times 10^{-1}$ $1.30\times 10^{-3}$

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$CO_2$ $3.33\times 10^{-4}$ $3.50\times 10^{-2}$

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<u>Explanation:</u>

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

$p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}$

where,

$p_A$ = partial pressure of hydrogen gas = ?

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$\chi_A$ = mole fraction of hydrogen gas = $5.00\times 10^{-7}$

Putting values in above equation, we get:

$p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm$

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

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