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Kitty [74]
3 years ago
9

The number of column inches of classified advertisements appearing on Mondays in a certain daily newspaper is normally distribut

ed with population mean of 320 and population standard deviation of 20 inches. For a randomly chosen Monday, what is the probability there will be between 280 and 360 column inches of classified advertisement?
Mathematics
1 answer:
lana66690 [7]3 years ago
6 0

Answer:

The probability there will be between 280 and 360 column inches of classified advertisement

P(280≤X≤360) = P(-2≤Z≤2) = 0.9544

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean  the population = 320

The standard deviation of the Population = 20

Let 'X' be the random variable in a normal distribution

Let 'X' = 280

Z = \frac{x-mean}{S.D} = \frac{280-320}{20} = -2

Let 'X' = 360

Z = \frac{x-mean}{S.D} = \frac{360-320}{20} = 2

<u><em>Step(iii):-</em></u>

The probability there will be between 280 and 360 column inches of classified advertisement

P(280≤X≤360) = P(-2≤Z≤2)

                        = P(z≤2) -P(z≤-2)

                       = P(z≤2)+P(z≤2)

                      = 2P(z≤2)

                     = 2×0.4772     ( from normal table)

                    = 0.9544

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Step-by-step explanation:

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4 years ago
Will mark BRAINLIEST to correct answer! Please help, this has to be correct. Thanks!
pogonyaev
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alexandr1967 [171]

Answer:

So there is a 2 in 13 chance to pull out either an ace or king from the deck

Step-by-step explanation:

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2 years ago
Could someone help me on this
allochka39001 [22]

Answer:

13.) 314.2 in²

15.) 181.5 ft²

Step-by-step explanation:

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In this equation, "π" represents the number pi (3.14....) and "r" represents the radius (half the diameter).

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2 years ago
A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

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Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

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Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)

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The probability that a household has at least one of these appliances is 0.95

3 0
3 years ago
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