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2 years ago

How many times does 12 go into 78

Mathematics

2 answers:

nirvana33 [79]2 years ago

7 0

Answer: 6.5? I think this is the answer but not sure.

andrew-mc [135]2 years ago

4 0

Answer:

Step-by-step explanation:

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Pleaseeee help meeeeeee

Maslowich

That my dear your answer would be 16 degrees hope this helped

5 0

3 years ago

Factor the expression<br> 3x +9 <br>The factored expression is....

muminat

Answer:

i believe it's "(x+3)(x+3)(x+3)" but double check me on that.

5 0

2 years ago

a cookie recipe calls for 5/8 cup of flour and 5/6 cup of sugar what is the least common denominator of the fractions A 6 B 12 C

serious [3.7K]

I think its 24 because 6*2 equals 12 but you cant multiply 8 by anything to get 12
with 24 6*4 equals 24 and 8*3 equals 24

6 0

3 years ago

Read 2 more answers

Paul says that (3.14 X 10^5) + (2.53 X 10^4) = 5.67 X 10^5. Is Paul correct? Explain.

Marizza181 [45]

He is false the equation should be as follows

3 0

2 years ago

Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u

cestrela7 [59]

Answer:

The amount of nuclear fuel required is 1.24 kg.

Step-by-step explanation:

From the principle of mass energy equivalence we know that energy generated by mass 'm' in an nuclear plant is

$E=m\cdot c^2$

where

'c' is the speed of light in free space

Since the power plant operates at 1200 MW thus the total energy produced in 1 year equals

$E=1200\times 10^6\times 3600\times 24\times 365=3.8\times 10^{16}Joules$

Thus using the energy produced in the energy equivalence we get

$3.8\times 10^{16}=mass\times (3\times 10^{8})^2\\\\\therefore mass=\frac{3.8\times 10^{16}}{9\times 10^{16}}=0.422kg$

Now since the efficiency of conversion is 34% thus the fuel required equals

$mass_{required}=\frac{0.422}{0.34}=1.24kg$

8 0

3 years ago