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3 years ago

CAN SOMEONE HELP PLSS ASAP! 20 points if yhu do help

Mathematics

1 answer:

Bas_tet [7]3 years ago

6 0

Answer:

2. x/-5 = 22

3. Multiply both sides by -5

4. x = -110

Step-by-step explanation:

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His new employer has offered Malcom Davis a choice of profit-sharing plans. For Plan A, he can receive 1/90 of the company’s gro

Strike441 [17]

Malcom Davis earnings is an illustration of equations and proportions.

The equation is: $\mathbf{\frac{1}{90}G= \frac{1}{60}(G- 100000)}$
The gross income must be $300000, for Dave to earn the same amount with either plan.
His earning is $3333.33 when the plans are the same.

Let the profit be P, and the gross income be G.

So, we have:

$\mathbf{P= G - 100000}$

(a) The equations

For plan A, we have:

$\mathbf{A = \frac{1}{90}G}$ ----1/90 of the company's gross income

For plan B, we have:

$\mathbf{B = \frac{1}{60}P}$ ----1/90 of the company's profit

When both are the same, we have:

$\mathbf{A= B}$

This gives

$\mathbf{\frac{1}{90}G= \frac{1}{60}P}$

Substitute $\mathbf{P= G - 100000}$

$\mathbf{\frac{1}{90}G= \frac{1}{60}(G- 100000)}$

Hence, the equation is: $\mathbf{\frac{1}{90}G= \frac{1}{60}(G- 100000)}$

(b) Solve the equation in (a), and intepret

$\mathbf{\frac{1}{90}G= \frac{1}{60}(G- 100000)}$

Cross multiply

$\mathbf{60G = 90G - 9000 000}$

Collect like terms

$\mathbf{90G - 60G = 9000 000}$

$\mathbf{30G = 9000 000}$

Divide both sides by 30

$\mathbf{G = 3000 00}$

The gross income must be $300000, for Dave to earn the same amount with either plan.

(c) His earnings based on (c)

We have:

$\mathbf{A = \frac{1}{90}G}$

Substitute $\mathbf{G = 3000 00}$

$\mathbf{A = \frac{1}{90} \times 300000}$

$\mathbf{A = 3333.33}$

His earning is $3333.33 when the plans are the same

(d) If the gross income in less than (b)

If the gross income is less than $300,000, then plan A would better for Malcom Davis, because his earnings in plan A would be greater than plan B

Read more about equations at:

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8 0

3 years ago

Simplify: (4b + 3) (2b - 5).

igomit [66]

(4b+3) (2b−5)

(4b+3) (2b+−5)

(4b) (2b) + (4b) (−5) +(3) (2b) +(3) (−5)

8b²−20b+6b−15.

= 8b²−14b−15.

5 0

4 years ago

Hailey received some cash for birthday. She spent $14.48 on a CD and donated $25.00 to charity. She put half of what was left in

DaniilM [7]

Work backwards.

After she put half of what she had left in, she had 17.76.

Multiply by 2:

17.76 * 2 = 35.52

Add 25:

35.52 + 25 = 60.52

Add 14.48:

75

So she received $75 on her birthday.

8 0

3 years ago

Read 2 more answers

Solve for x THANK YOU

Anestetic [448]

Answer:

$x=\dfrac{-17+ \sqrt{451} }{18}, \quad x=\dfrac{-17- \sqrt{451} }{18}$

Step-by-step explanation:

$\textsf{Given equation}:$

$\dfrac{2}{3}x+\dfrac{3x}{x}=\dfrac{4x}{2}(3x+6)$

$\textsf{Cancel the common factor } x \textsf{ in }\dfrac{3x}{x}:$

$\implies \dfrac{2}{3}x+3=\dfrac{4x}{2}(3x+6)$

$\textsf{Simplify }\dfrac{4x}{2}\textsf{ by dividing the numbers}:$

$\implies \dfrac{2}{3}x+3=2x(3x+6)$

$\textsf{Apply the distributive law}\quad \:a\left(b+c\right)=ab+ac:$

$\implies \dfrac{2}{3}x+3=6x^2+12x$

$\textsf{Multiply both sides by 3 to cancel the denominator of }\dfrac{2}{3}:$

$\implies \dfrac{2}{3}x\cdot 3+3\cdot 3=6x^2\cdot 3+12x \cdot 3$

$\implies 2x+9=18x^2+36x$

$\textsf{Switch sides}:$

$\implies 18x^2+36x=2x+9$

$\textsf{Subtract }2x \textsf{ from both sides}:$

$\implies 18x^2+36x-2x=2x+9-2x$

$\implies 18x^2+34x=9$

$\textsf{Subtract 9 from both sides}:$

$\implies 18x^2+34x-9=9-9$

$\implies 18x^2+34x-9=0$

Solve using the Quadratic Formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Define the variables:

$\implies a=18, \quad b=34, \quad c=-9$

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-34 \pm \sqrt{34^2-4(18)(-9)} }{2(18)}$

$\implies x=\dfrac{-34 \pm \sqrt{1156+648} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{1804} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{4 \cdot 451} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{4}\sqrt{451} }{36}$

$\implies x=\dfrac{-34 \pm 2\sqrt{451} }{36}$

$\implies x=\dfrac{-17 \pm \sqrt{451} }{18}$

Therefore, the solutions to the given equation are:

$x=\dfrac{-17+ \sqrt{451} }{18}, \quad x=\dfrac{-17- \sqrt{451} }{18}$

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3 0

2 years ago

Read 2 more answers

PRE-CAL HELP PLEASE (see attachment)

lana66690 [7]

Answer:

$\lim_{x \to \infty} \frac{2500 + 17(x-100)}{x}=17$

Explanation:

1) Charges are:

Flat fee: 500
First 100 tickets: 20(100) = 2000
Tickets over 100: 17 ( x - 100), where x is the number of tickets.

2) Total charges: 500 + 2000 + 17(x - 100) = 2500 + 17(x - 100)

3) Average cost per ticket = total charges / number of tickets

⇒ [2500 + 17(x - 100) ] / x

4) limit as the number of tickets, x, becomes very high ⇒ x → ∞

⇒ $\lim_{x \to \infty} \frac{2500 + 17(x-100)}{x}$

5) And the value of that limit is equal to 17, as shown below:

2500 / x + 17x / x - 1700/x = 0 + 17 + 0 = 17

8 0

3 years ago