15%=3
5%=1
5(20)=100
1(20)=20
So, there are 20 students in the class.
Division phrases:
-divided by
-percent of
-ratio of <span />
Answer: 
Step-by-step explanation:
<h3>
"Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree, which was in the middle of the park, at the origin. She plotted a maple tree, which was 10 yards away from the oak tree, at the point (10,0) . Then she plotted a pine tree at the point (-2.4, 5) and an apple tree at the point (7.8, 5) What is the distance, in yards, between the pine tree and the apple tree in the</h3><h3>
park?"</h3>
For this exercise you need to use the following formula, which can be used for calculate the distance between two points:

In this case, you need to find distance, in yards, between the pine tree and the apple tree in the park.
You know that pine tree is located at the point (-2.4, 5) and the apple tree is located at the point (7.8, 5).
So, you can say that:

Knowing these values, you can substitute them into the formula and then evaluate, in order to find the distance, in yards, between the pine tree and the apple tree in the park.
This is:

Answer:
(-8,-4) and (-2,5). at reflect on x axis
Answer: [H+] = 10^-7.2
Step-by-step explanation:
Given that the PH of the solution = 7.2
Using the formula pH = –log[H+]. To get the H+ concentration from the pH, raise both sides by the base of 10. Then we have
10^ -pH = H+. with pH of 7.2,
Thus the answer to this problem is
[H+] = 10^-7.2