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wariber [46]
3 years ago
8

Surface area of a sphere with radius 19

Mathematics
2 answers:
puteri [66]3 years ago
7 0

Answer:

A≈4536.46

Step-by-step explanation:

I hope this helps! ^^

☁️☁️☁️☁️☁️☁️☁️

Tom [10]3 years ago
5 0

Answer:

<em>Radius</em><em> </em><em>1</em><em>9</em><em> </em>

A ≈ 4536.46 .....ans

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Find the values of the variables in this kite.
zavuch27 [327]

Answer:

x=7, y=16

Step-by-step explanation:

2x+5=x+12

2x=x+7

x=7

y-4=x+5

y-4=12

y=16

4 0
4 years ago
Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

Calculate the angle between u and v

The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

|v| = \sqrt{16+49}

|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

4 0
3 years ago
If the radius of a circle is 16 units, what is its area? (Use pie for it)
krok68 [10]

Answer:

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Step-by-step explanation:

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3 years ago
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sukhopar [10]
N - 5 ≥ -2

5 - 5 ≥ -2 

5 - 5 = 0

n = 5

5 - 5 ≥ -2

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(0 ≥ -2)
3 0
3 years ago
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Answer:

I think b

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