That’s some Jesus math there buddy idek
The answer is 3. To find the interquartile range, all you have to do is subtract your Q3-Q1. In this case, all you do is
20-17=3
X = first venture, y = second venture, z = third venture
x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....
x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000
x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000
2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000
x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000
first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
Answer:
c
Step-by-step explanation:
-7.5 is less than 6.5
Answer:
The area of DBE = 27 square units
Step-by-step explanation:
Area of ABC = 3 square units
In the figure, we can see that ABC was enlarged so that BDE is formed where side BD = 6 and AB was = 2
Hence ABC was enlarged 3 times its size.
We know by formula that:
Area of ABC = 1/2(base x perpendicular)
3 = 1/2(2 x p)
=> p = 3
As ABC was enlarged 3 times its size, the perpendicular of BDE must be 3*p
= 3*3 = 9
AREA OF DBE = 1/2(base*perp)
= 1/2(6*9)
= 27 square units
