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Vesnalui [34]
3 years ago
5

In the electric currect​ flow, it is found that the resistance​ (measured in the units called​ ohms) offered by a fixed length o

f wire of a given material varies inversely as the square of the diameter of the wire. If a wire 0.01 in. in diameter has a resistance of 0.4560.456 ​ohm, what is the resistance of a wire of the same length and material with diameter 0.04010.0401 in. to the nearest​ ten-thousandth?
The resistance of a wire is
nothing ohm.
​(Round to the nearest​ ten-thousandth.)
Enter your answer in the answer box and then click Check Answer.

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Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0
Let x be the resistance of the wire with the larger diameter.
x = (0.456 x (0.01)^2)/(0.0401)^2 = 0.0284 ohms
The answer is 0.0284 ohms.

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Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the box plot is not attached.

However, the interpretation of the question is to determine the inter-quartile range (IQR) ; this represents the middle 50% of scores

To answer this question, I will make use of the attached box plot.

IQR is calculated as:

IQR = Q_3 - Q_1

Q_1 and Q_3 are represented by the vertical edges of the rectangle in the box plot. [See attachment]

Reading Q_1 and Q_3, we have:

Q_1 = 37

Q_3 = 50

The IQR is:

IQR = 50 - 37

IQR = 13

<em>Hence, the range that describes the middle 50% of the attached plot is 13</em>

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3 years ago
Solve this for most Brainly
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PLEASE HELP???!!!!!
Likurg_2 [28]
We'll use the Pythagorean Theorem
130^2 = side^2 +50^2
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side = square root (14,400)
side = 120 feet



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hjlf

Answer:

See below ~

Step-by-step explanation:

Based on the graph,

  1. <u>f(-3)</u>
  • f(-3) = 0

   2. <u>f(4)</u>

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   3. <u>x when f(x) = 5</u>

  • f(x) = 5
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   4. <u>x when f(x) = -3</u>

  • f(x) = -3
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