I need help with this question

Mathematics

1 answer:

aivan3 [116]3 years ago

4 0

Answer:

(C). $\frac{22\pi }{3}$ yd.

Step-by-step explanation:

You might be interested in

Which expression is equivalent to 18x2 – 50?

kondor19780726 [428]

Answer:

(3) 2(3x - 5)(3x + 5)

Step-by-step explanation:

$18 {x}^{2} - 50 \\ = 2(9 {x}^{2} - 25) \\ = 2(3x - 5)(3x + 5)$

6 0

3 years ago

in a factory that manufactures tires, a machine responsible for molding the tire has a failure rate of 0.2%. If 1,000 tires are

goldfiish [28.3K]

Okay, so let's find the actual failure rate first. 6/1000 times 100 (to give over a 100%) equals to 0.6. The actual failure rate is 0.6%. The theoretical probability is 0.2% 0.6-0.2=0.4. The difference is 0.4%.
Hope that helped!

4 0

3 years ago

Read 2 more answers

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$