Answer:
the answer to x is 4
Step-by-step explanation:
.
The perimeter is the total of adding all of the side lengths together.
A square has 4 equal side lengths.
So the perimeter of a square is:
P = s + s + s + s or P = 4s
[P = perimeter s = side lengths of the square]
Since you know the side length of the square is (x + 2 1/4), you can replace s with (x + 2 1/4)
P = 4s
P = 4(x + 2 1/4) Multiply 4 into (x + 2 1/4)
P = 4x + 8 4/4
P = 4x + 9
Since you know the perimeter, you can plug it in.(you could have also plugged it in in the beginning)
P = 4x + 9
14 = 4x + 9 Subtract 9 on both sides
5 = 4x Divide 4 on both sides
5/4 = x
Now that you know x, find the side length of the square.
(x + 2 1/4)
(5/4 + 2 1/4)
2 6/4 = 3 2/4 = 3 1/2 units or 3.5 units
To find the area of a square, you multiply 2 of the sides together:
A = s · s
A = 3.5 · 3.5
A = 12.25 units²
Answer:
49
Step-by-step explanation:
Answer:
![E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}](https://tex.z-dn.net/?f=E%28X%29%3D%20n%20%5Cint_%7B0%7D%5E1%20x%5En%20dx%20%3D%20n%20%5B%5Cfrac%7B1%7D%7Bn%2B1%7D-%20%5Cfrac%7B0%7D%7Bn%2B1%7D%5D%3D%5Cfrac%7Bn%7D%7Bn%2B1%7D)
Step-by-step explanation:
A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".
We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).
If we select a value
we want this:

And we can express this like that:
for each possible i
We assume that the random variable
are independent and
from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:

And then cumulative distribution would be expressed like this:



For each value
we can find the dendity function like this:

So then we have the pdf defined, and given by:
and 0 for other case
And now we can find the expected value for the random variable X like this:

![E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}](https://tex.z-dn.net/?f=E%28X%29%3D%20n%20%5Cint_%7B0%7D%5E1%20x%5En%20dx%20%3D%20n%20%5B%5Cfrac%7B1%7D%7Bn%2B1%7D-%20%5Cfrac%7B0%7D%7Bn%2B1%7D%5D%3D%5Cfrac%7Bn%7D%7Bn%2B1%7D)
Answer:
y = -4x - 32
Step-by-step explanation:
First, find the slope using rise over run (y2 - y1) / (x2 - x1)
Plug in the points:
(y2 - y1) / (x2 - x1)
(8 - 4) / (-10 + 9)
4 / -1
= -4
So, the slope is -4. Plug in the slope and a point into y = mx + b, and solve for b:
y = mx + b
4 = -4(-9) + b
4 = 36 + b
-32 = b
Then, plug in the slope and y intercept into y = mx + b
y = -4x - 32 is the equation of the line