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nalin [4]
3 years ago
12

Car rideshare services are a popular option for people needing to move about in large cities. The scatterplot shows the distance

s of trips and fares, in dollars, for an adult living in a city over a period of a month. The value of r for the scatterplot is 0.950.
How would the value of the correlation coefficient change if the fares were plotted on the x-axis and distances on the y-axis?

The value of the correlation coefficient would be –0.950.
The value of the correlation coefficient would not change.
The value of the correlation coefficient would be closer to 0.
The value of the correlation coefficient would be closer to 1.
Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0

Answer:

The value of the correlation coefficient would not change.

Step-by-step explanation:

If the relationship between distance of trips and fares in dollars gives a correlation coefficient value of 0.950. This can be interpreted to mean that the relationship between both variables is strong and positive such that an increase in distance leads to corresponding increase in fares of the trip and vice versa. Thus, interchanging the axis upon which the variables are plotted would still tied the same correlation Coefficient value as the correlation coefficient does not depend on the axis upon which the variables are plotted.

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9)  p = 48

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Read 2 more answers
If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?
Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor  (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2

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So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

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3 years ago
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