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harkovskaia [24]
3 years ago
13

Ella can fill six 250ml glasses from abottle. How big is the bottle in litres?​

Mathematics
2 answers:
NemiM [27]3 years ago
5 0
6x250=1500
In litres /1000
1.5 litres
insens350 [35]3 years ago
5 0

Answer:

1.5 litres

Step-by-step explanation:

Amount of water in bottle: 250 x 6 = 1500 (ml)

1500 ml = 1.5 litres

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a sign says that the price marked on all music equipment is 30% off the original price you buy an electric guitar for sale price
prohojiy [21]

The original price is $450.

<u>Step-by-step explanation:</u>

Step 1:

Given details, Discount%, D% = 30 and Selling Price, SP = $315

Step 2:

Write down formula for calculating the Original Price

Selling Price (SP) = Original Price (OP) - Discount (D)

Discount (D) = Original Price (OP) * (D%/100)

Step 3:

Substitute given values in the formula

315 = OP - D

D = OP \times30/100

D = 0.3 OP

Step 4:

Substitute value of D in the first formula

315 = OP - 0.3 OP

315 = OP (1 - 0.3) = 0.7 OP

Original Price, OP = 315/0.7 = $450

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4 years ago
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4 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

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3 years ago
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Burka [1]

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3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
rjkz [21]

Answer:

Its 41 mph and 55 mph

Step-by-step explanation:

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3 years ago
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