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mariarad [96]
3 years ago
11

Rowan is taking his siblings to get ice cream. They can't decide whether to get a cone or a cup because they want to get the mos

t ice cream for their money. If w = 4 in, x =6 in, y = 6 in, z = 2 in, and the cone and cup are filled evenly to the top with no overlap, which container will hold the most ice cream? Use 3.14 for π, and round your answer to the nearest tenth.
a cone with a height of x and a radius of w, a cylinder with a diameter of y and a height of z

The cup holds 56.52 in3 more ice cream than the cone.
The cone holds 56.52 in3 more ice cream than the cup.
The cup holds 43.96 in3 more ice cream than the cone.
The cone holds 43.96 in3 more ice cream than the cup.
Mathematics
2 answers:
drek231 [11]3 years ago
6 0

Answer:

The cup holds 56.52 in3 more icecream than the cone

Step-by-step explanation:

im pretty sure of it.

Luba_88 [7]3 years ago
6 0

Answer:

C. The cup holds 43.96 in3 more ice cream than the cone.

Step-by-step explanation:

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Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

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Step-by-step explanation:

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\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

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=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

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3 years ago
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