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ruslelena [56]
4 years ago
15

Which region labeled in the graph below would represent the solution (the final shaded area) to the system of linear inequalitie

s: y≤1/2x−3 y<−2/3x+1 Group of answer choices Region C, Region D, Region A, Region B

Mathematics
1 answer:
Elena L [17]4 years ago
5 0

Answer:

Region D.

Step-by-step explanation:

Here we have two inequalities:

y ≤ 1/2x − 3

y < −2/3x + 1

First, we can see that the first inequality has a positive slope and the symbol (≤) so the values of the line itself are solutions, this line is the solid line in the graph.

And we have that:

y ≤ 1/2x − 3

y must be smaller or equal than the solid line, so here we look at the regions below the solid line, which are region D and region C.

Now let's look at the other one:

y < −2/3x + 1

y = (-2/3)*x + 1

is the dashed line in the graph.

And we have:

y < −2/3x + 1

So y is smaller than the values of the line, so we need to look at the region that is below de dashed line.

The regions below the dashed line are region A and region D.

The solution for the system:

y ≤ 1/2x − 3

y < −2/3x + 1

Is the region that is a solution for both inequalities, we can see that the only region that is a solution for both of them is region D.

Then the correct option is region D.

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In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct a 95% conden
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Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that n = 42, \pi = \frac{26}{42} = 0.619

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 - 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.472

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 + 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.766

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

4 0
3 years ago
Amery drive 50 miles in 1 hour. how many hours does he drive in 2.25 hours
Mariana [72]
Amery drive 120 miles
7 0
4 years ago
Which equation represents a direct variation?
8090 [49]

Answer:

Y = x y = kx. When the equation that describes direct variance is graphed in the Cartesian Plane, there is always a straight line moving through the origin. Think of it as the Slope-Intercept Shape of a line written as y = mx + b y = mx + b.

Step-by-step explanation:

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3 years ago
Find the point, M, that divides segment AB into a ratio of 5:5 if A is at (0, 15) and B is at (20, 0).
Airida [17]

C

a ratio of 5 : 5 simplifies to 1 : 1, which basically means we require the midpoint of the line segment

using the midpoint formula

M = [\frac{1}{2} (0 + 20 ), \frac{1}{2} (15 + 0)] = (10, 7.5 )


5 0
3 years ago
Read 2 more answers
What is the area of the shaded region? (Approximate π to be 3.14)
kifflom [539]

Answer:

  about 113.04 square inches

Step-by-step explanation:

No angles are indicated, so we must assume the sector is 1/4 of the circle. Then its area is 1/4 of that of a circle with radius 12 in:

  Circle area = πr²

  Sector area = (1/4)π(12 in)² = 36π in²

  Sector area ≈ 36(3.14) in² = 113.04 in²

7 0
3 years ago
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