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jeka57 [31]
3 years ago
8

Please help im trying to finish a test

Mathematics
2 answers:
Yuki888 [10]3 years ago
6 0

Answer:

16

4^2= 4*4= 16

Hoochie [10]3 years ago
5 0

Answer:

A= 16²

Step-by-step explanation:

A=s²

A= 4²

A= 16

(4² is the same as 4x4)

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If a boat depreciates in value according to the simple interest formula Y=20,000(.92)^2 find the rate of decay. Write as a perce
zhenek [66]

Answer:

$28,000

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The scores of fourth grade students on a mathematics achievement test follow a normal distribution with a mean of 75 and standar
mamaluj [8]

Answer:

The appropriate solution is:

(a) 0.1056

(b) 0

(c) 0.9544

Step-by-step explanation:

The given values are:

Mean,

\mu = 75

Standard deviation,

\sigma = 4

(a)

⇒  P(x>80)=1-(x

                     =1-P[\frac{x-\mu}{\sigma}

                     =1-P[\frac{x-\mu}{\sigma}

                     =1-P(z

By using the table, we get

                     =1-0.8944

                     =0.1056

(b)

According to the question, the values are:

n = 64

\mu_\bar{x} = 75

Now,

⇒  \sigma_\bar{x} = \frac{\sigma}{\sqrt{n} }

         = \frac{4}{\sqrt{64} }

         = \frac{4}{8}

         = 0.5

⇒  P(\bar {x} >80 ) = 1 - P(\bar x

                      =1 - P[\frac{(\bar x-\mu_\bar x)}{\sigma \bar x} < \frac{80-75}{0.5}  ]

                      =1-P(z

By using the table, we get

                      =1-1

                      =0

(c)

As we know,

⇒ \sigma_\bar x = \frac{\sigma}{\sqrt{n} }

        = \frac{4}{\sqrt{64} }

        = \frac{4}{8}

        = 0.5

then,

= P(74< \bar x

= P[\frac{74-75}{0.5} < \frac{\bar x-\mu \bar x}{\sigma \bar x} < \frac{76-75}{0.5} ]

= P(-2

= P(z

By using the table, we get

= 0.9772-0.0228

= 0.9544

7 0
3 years ago
Write an equivalent expression for 4(3a+7)+3 (2a+5) if a=5, is the the solution to both expressions the same
Levart [38]
<span>Alternative</span>
4(3*5+7)+3(2*5+5)=
4(22)+3(15)=
(4*22)+(3*15)=
88+45=133

4 0
3 years ago
Read 2 more answers
The human ear disinguish sounds between 20 hz and 20,000 hz, inclusive write a compound inequality for the problem.
worty [1.4K]
20 > x < 20,000

X = Range of human ear
3 0
4 years ago
How do you simplify 3(y-8)+3(2y)
SIZIF [17.4K]

Answer:

9y-24

Step-by-step explanation:

3(y-8)+3(2y)

3y-24+6y

9y-24

7 0
3 years ago
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