Answer:
Step-by-step explanation:
Let
h(t) ---> the height of an object in meters
t ----> the time in seconds
we have
For t=6 sec
substitute in the quadratic equation the value of t and solve for h
A chocolate bar measures 50 mm wide, 90 mm long, and mm high. Will’s Wrapping Company is making a wrapper to cover the chocolate
bar. Use the correct net and determine how much paper will be needed to make the wrapper.
A.Will’s Wrapping Company needs 4,640 mm2 of paper to wrap the chocolate bar.
B.Will’s Wrapping Company needs 4,990 mm2 of paper to wrap the chocolate bar.
C.Will’s Wrapping Company needs 9,980 mm2 of paper to wrap the chocolate bar.
D.Will’s Wrapping Company needs 19,960 mm2 of paper to wrap the chocolate bar.
A.Will’s Wrapping Company needs 4,640 mm2 of paper to wrap the chocolate bar.
B.Will’s Wrapping Company needs 4,990 mm2 of paper to wrap the chocolate bar.
C.Will’s Wrapping Company needs 9,980 mm2 of paper to wrap the chocolate bar.
D.Will’s Wrapping Company needs 19,960 mm2 of paper to wrap the chocolate bar.
1 answer:
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Let
x----------> the first mechanic rates
y----------> the second mechanic rates
we know that
x+y=165
15x+5y=1775
using a graph tool
see the attached figure
the solution is
x=95
y=70
the answer is
the rates of the first mechanic is 95
the rates of the second mechanic is 70
x----------> the first mechanic rates
y----------> the second mechanic rates
we know that
x+y=165
15x+5y=1775
using a graph tool
see the attached figure
the solution is
x=95
y=70
the answer is
the rates of the first mechanic is 95
the rates of the second mechanic is 70