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3 years ago

12

How does the mean and median change from plot 1 to plot 2?

2 answers:

Elena-2011 [213]3 years ago

8 0

Answer:

It’s B maybe not 100%

sure

Step-by-step explanation:

lol tell me if I’m correct

creativ13 [48]3 years ago

4 0

Question:

How does the mean and median change from plot 1 to plot 2?

<em>A.</em><em>The mean and median remain the same. </em>

<em>B.</em><em>The mean decreases, and the median remains the same. </em>

<em>C.</em><em>The mean remains the same, and the median decreases. </em>

<em>D.</em><em>The mean and median decrease.</em>

Answer:

<em>B.</em><em>The mean decreases, and the median remains the same.</em>

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What is the general form of the equation for the given circle centered at [0, 0)?

sergejj [24]

Answer:

x^2+y^2=r^2 is quation of circle whose centre is (0,0)

3 0

3 years ago

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

3 years ago

What is -5(7x + 2) =200

blondinia [14]

Your answer is going to be X=-6

3 0

3 years ago

Read 2 more answers

When calculating the circumference of a circle, sometimes the radius is given instead of the diameter. What is the relationship

Gwar [14]

The diameter is equal to the radius multiplied by 2.

3 0

3 years ago

-52 times the difference between a number and 14 is equal to the number plus 3

xenn [34]

X=number looked for
we have this equation:
-52(x-14)=x+3
we solve this equation:
-52x+728=x+3
-52x-x=3-728
-53x=-725
x=-725/-53=725/53 ≈13,68

Solution: 725/53

To check:
the difference between 725/53 and 14=725/53 - 14=(725-742)/53=-17/53
-52 times the diference is= -52(-17/53)=884/53
The number plus 3=725/53 + 3=(725+159)/53=884/53

3 0

3 years ago