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Simora [160]
3 years ago
14

Write an equation and solve. Round to the nearest hundredth where necessary.

Mathematics
1 answer:
ioda3 years ago
4 0
The answer to the question is b I think.
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Jean's bedroom is 11 feet by 14 feet. She has chosen a carpet which costs $33.30 per square yard. This includes installation.
Allisa [31]

Answer:

The room will cost $569.80 to carpet.

Step-by-step explanation:

Recall that 1 square yard = 9 square feet.

The area of the bedroom, in square feet, is (11 ft)(14 ft) = 154 ft^2.

Converting this to square yards:

154 ft^2      1 yd^2

------------ * ------------ = 17.1 yd^2

       1          9 ft^2

17.1 yd^2     $33.30

------------- * ------------- = $569.80

       1            1 yd^2

The room will cost $569.80 to carpet.

5 0
3 years ago
What is the answer 6.25=r2
Rom4ik [11]
The opposite of multiplication is division, so you divide 2 from both sides. R2/2 = cancel out 6.25/2 = 3.125 R = 3.125
3 0
4 years ago
Read 2 more answers
John has 15 1/4 gallons of gas in his truck. John can drive his truck 7 1/2 miles on each gallon of gas. About how many miles ca
photoshop1234 [79]

Answer:

114 3/8 gallons

Step-by-step explanation:

To solve the question, we multiply by the number of gallons and the amount travelled per gallon:

Let's convert all fractions to improper fractions:

15 1/4 = (15*4 + 1)/4 = 61/4

7 1/2 = (7*2 + 1)/2 = 15/2

Multiply the numerators and the denominators:

61/4 * 15/2 = 61*15/4* 2 = 915/8 = 114 3/8

-Chetan K

3 0
3 years ago
A. -3<br> B. -4<br> C. -2 and 1<br> D. 0
Alinara [238K]
When x=1 and -2 so it is C
8 0
4 years ago
Read 2 more answers
C(x)=x^3-2x^2+8x+50. find the critical numbers
sattari [20]
\large\begin{array}{l} \textsf{Finding the critical points of a given function:}\\\\ \mathsf{C(x)=x^3-2x^2+8x+50}\\\\\\ \bullet~~\textsf{1}\mathsf{^{st}}\textsf{ step: Find the derivative of C(x):}\\\\ \mathsf{C'(x)=(x^3-2x^2+8x+50)'}\\\\ \mathsf{C'(x)=3x^{3-1}-2\cdot 2x^{2-1}+8\cdot 1+0}\\\\ \mathsf{C'(x)=3x^2-4x+8} \end{array}


\large\begin{array}{l} \bullet~~\textsf{2}\mathsf{^{nd}}\textsf{ step: Solve the equation } \mathsf{C'(x)=0:}\\\\ \mathsf{3x^2-4x+8=0}\quad\Rightarrow\quad\begin{cases}\mathsf{a=3}\\\mathsf{b=-4}\\\mathsf{c=8} \end{cases}\\\\ \mathsf{\Delta=b^2-4ac}\\\\ \mathsf{\Delta=(-4)^2-4\cdot 3\cdot 8}\\\\ \mathsf{\Delta=16-96}\\\\ \mathsf{\Delta=-80


\large\begin{array}{l} \textsf{Since the discriminant is a negative number, there's no}\\\textsf{real solution for }\mathsf{C'(x)=0.}\\\\\\ \textsf{Therefore, }\mathsf{C(x)}\textsf{ doesn't have any critical point.} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2150969


\large\textsf{I hope it helps.}


Tags: <em>critical points numbers function derivative differential calculus</em>

4 0
3 years ago
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