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Reika [66]
3 years ago
15

Which function is nonlinear?

Mathematics
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

C and E

Step-by-step explanation:

c) \:  \: y = 2 + 6 {x}^{4}  \\  \\ e) \:  \:  \frac{x}{y}  + 1 = 2 \\  \\ are \: non \: linear

RSB [31]3 years ago
4 0

Answer:

option C

Step-by-step explanation:

if a function is linear then we know that the highest exponent is 1

so we just look for a function that doesn't have an exponent of 1 and that's option C which has an exponent of  4

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Which is the value of x in the equation?<br> 4(x-3) = 40
mario62 [17]

Answer:14

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A travel agent is booking a trip to England, Scotland, Ireland, and France for a group of senior citizens. The agent sent survey
elixir [45]

Answer: 1

Scotland

Step-by-step explanation:

In the first vote, points are:

France = 15

England = 12 + 16 = 28

Ireland = 19

2nd vote

England = 15

Scotland = 12 + 19 = 31

Ireland = 16

3rd vote

Scotland = 15 + 16 = 31

Ireland = 12

England = 19

4th vote

Ireland = 15

France = 12 + 16 + 19 = 47

At the end of everything

England = 19 + 15 + 28 = 62

France = 15 + 47 = 62

Scotland = 31 + 31 = 62

Ireland = 19 + 16 + 12 + 15 = 62

To find the Condorcet winner, the number of votes for runner over opponent (runner,opponent) is compared with the number of votes for opponent over runner (opponent,runner)  

Only Scotland has the highest (31) points twice.

6 0
3 years ago
At the skating rink, 6 out 10 skaters were able to skate under the limbo bar. Which names the fraction of skaters who were not a
Tasya [4]
2/5 because 10/10 minus 6/10 equals 4/10 which reduces to 2/5
7 0
3 years ago
Which of the expressions below are equal to 5x + 20y? Select all that apply.
xeze [42]
The correct answers are A and B.
Hope this helps!
8 0
3 years ago
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Find the value of x (3/5)^x(5/3)^2x=125/27​
lesya692 [45]

Given:

The equation is

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

To find:

The value of x.

Solution:

We have,

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

\left(\dfrac{5}{3}\right)^{-x}\left(\dfrac{5}{3}\right)^{2x}=\dfrac{5\times 5\times 5}{3\times 3\times 3}      [\because \left(\dfrac{a}{b}\right)^{-m}=\left(\dfrac{b}{a}\right)^{m}]

\left(\dfrac{5}{3}\right)^{-x+2x}=\dfrac{5^3}{3^3}          [\because a^ma^n=a^{m+n}]

\left(\dfrac{5}{3}\right)^{x}=\left(\dfrac{5}{3}\right)^{3}

On comparing the exponents, we get

x=3

Therefore, the value of x is 3.

8 0
3 years ago
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