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3 years ago

Name the triangle with the following characteristics. Sides: 5 cm, 5 cm, 7 cm.

Mathematics

2 answers:

Iteru [2.4K]3 years ago

6 0

I belive it might be a right triangle

lutik1710 [3]3 years ago

4 0

Isosceles triangle since two sides are equal

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A temperature recorded in Antarctica was -121Fahrenheit. The temperature recorded in the Sahara desert was 132 fahrenheit. How m

rodikova [14]

Answer: 253°F

Step-by-step explanation:

Given the following :

Temperature in Antarctica = - 121 Fahrenheit

Temperature in Sahara desert = 132 Fahrenheit

Number of degrees in which Sahara desert is warmer than Antarctica :

(temperature in Sahara desert - temperature in Antarctica)

= ( 132°F - (-121°F))

= (132°F + 121°F)

= 253°F

Sahara Desert is 253°F warmer

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4 years ago

Approximately 3 out of every 25 people are left-handed. How many left-handed

Liono4ka [1.6K]

Answer: 198 left handed students

Step-by-step explanation:

You have to divide the 1650 by 25 and that equals 66 then multiply by 3 and that equals 198

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3 years ago

Y = 6x + 5.<br><br><br> What does x equal?

statuscvo [17]

X = (Y - 5) / 6 so X is that

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3 years ago

1110 poeple in a ship and the ship gard said we have to split in to 10 ships how many poeple in each ship?

Lina20 [59]

Answer:

110

Step-by-step explanation:

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3 0

4 years ago

Read 2 more answers

The position of a model train, in feet along a railroad track, is given by

miv72 [106K]

Answer:

Part a) The speed is $2.5\frac{ft}{sec}$

Part b) After 4 seconds the trains is 24 ft along the track

Part c) $t=6\ sec$

Step-by-step explanation:

we have

$s(t)=2.5t+14$

This is the equation of a line in slope intercept form

where

s(t) is the position of a model train in feet

t is the time in seconds

Part a) How fast is the train moving?

The speed of the train is equal to the slope of the linear equation so

The slope m is equal to

$m=2.5\frac{ft}{sec}$

therefore

The speed is $2.5\frac{ft}{sec}$

Part b) Where is the train after 4 seconds?

For t=4 sec

substitute the value of t in the equation and solve for s

$s(4)=2.5(4)+14=24\ ft$

therefore

After 4 seconds the trains is 24 ft along the track

Part c) When will the train be 29 feet along the track?

For s(t)=29 ft

Substitute the value of s(t) in the equation and solve for t

$29=2.5t+14$

subtract 14 both sides

$29-14=2.5t$

$15=2.5t$

Divide by 2.5 both sides

$6=t$

rewrite

$t=6\ sec$

3 0

3 years ago