Answer:
I think the answer is 15.
Answer: A. negative 3 over 5 is located on the right of −2
Step-by-step explanation:
On a number line, the greater numbers are to the right and the smaller numbers are to the left.
Answer:
![d = 340.7m](https://tex.z-dn.net/?f=d%20%3D%20340.7m)
Step-by-step explanation:
See attachment for question illustration
From the attachment, we have:
![AB = 125m](https://tex.z-dn.net/?f=AB%20%3D%20125m)
![](https://tex.z-dn.net/?f=%3CA%20%3D%2041.6)
![](https://tex.z-dn.net/?f=%3CB%20%3D%20124.3)
Required
Solve d
First, we need to calculate <C
--- angles in a triangle
![41.6+ 124.3 +](https://tex.z-dn.net/?f=41.6%2B%20124.3%20%2B%20%3CC%20%3D%20180)
![165.9+](https://tex.z-dn.net/?f=165.9%2B%20%3CC%20%3D%20180)
Make <C the subject
![](https://tex.z-dn.net/?f=%3CC%20%3D%20180%20-%20165.9)
![](https://tex.z-dn.net/?f=%3CC%20%3D%2014.1)
Next, we apply Sine's law to solve for d
![\frac{A}{Sin\ A} = \frac{B}{Sin\ B} =\frac{C}{Sin\ C}](https://tex.z-dn.net/?f=%5Cfrac%7BA%7D%7BSin%5C%20A%7D%20%3D%20%5Cfrac%7BB%7D%7BSin%5C%20B%7D%20%3D%5Cfrac%7BC%7D%7BSin%5C%20C%7D)
In this case:
![\frac{d}{Sin\ 41.6} = \frac{125}{Sin\ 14.1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7BSin%5C%2041.6%7D%20%3D%20%5Cfrac%7B125%7D%7BSin%5C%2014.1%7D)
Make d the subject
![d = \frac{125 * sin\ 41.6}{sin 14.1}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B125%20%2A%20sin%5C%2041.6%7D%7Bsin%2014.1%7D)
![d = \frac{125 * 0.66392621265}{0.24361501178}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B125%20%2A%200.66392621265%7D%7B0.24361501178%7D)
![d = \frac{82.9907765812}{0.24361501178}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B82.9907765812%7D%7B0.24361501178%7D)
![d = 340.663639629](https://tex.z-dn.net/?f=d%20%3D%20340.663639629)
![d = 340.7m](https://tex.z-dn.net/?f=d%20%3D%20340.7m)
<em>Hence, the base of the lake is approximately 340.7m</em>
Answer:
f^-1(x) is 6x + 48
f(x) = 1/6x - 8
To find f^-1(x) equate f(x) to y
That's
f(x) = y
y = 1/6x - 8
Next interchange the terms
We have
x = 1/6y - 8
Make y the subject
Multiply through by 6
We have
6x = y - 48
y = 6x + 48
Therefore f^-1(x) is 6x + 48
Hope this helps you