Answer:
t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490
Step-by-step explanation:
Solve for t:
4.9 t^2 - 2.78 t - 1.15 = 0
4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20:
(49 t^2)/10 - (139 t)/50 - 23/20 = 0
Multiply both sides by 10/49:
t^2 - (139 t)/245 - 23/98 = 0
Add 23/98 to both sides:
t^2 - (139 t)/245 = 23/98
Add 19321/240100 to both sides:
t^2 - (139 t)/245 + 19321/240100 = 75671/240100
Write the left hand side as a square:
(t - 139/490)^2 = 75671/240100
Take the square root of both sides:
t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490
Add 139/490 to both sides:
t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490
Add 139/490 to both sides:
Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490
Answer:
Step-by-step explanation:
<u>Addition Law for Probability</u>
Given:
Substitute the given values into the formula and solve for P(A ∩ B):
Answer:
A
Step-by-step explanation:
point H is the point of intersection of the perpendicular bisectors of the triangle's sides and is the circumcentre.
Answer:
-4w+32
-10p+40
-2g+4
Step-by-step explanation:
distribute
a negative minus a negative is a positive
<h2><em><u>xoxo, </u></em></h2><h2><em><u>your highness...</u></em></h2>
The formula<span> for the </span>equation<span> of a </span>circle<span> is (x – h)</span>2+ (y<span> – k)</span>2<span> = r</span>2<span>, where (h, k) represents the coordinates of the </span>center<span> of the </span>circle<span>, and r represents the radius of the </span>circle<span>. If a </span>circle<span> is </span>tangent<span> to the x-</span>axis<span> at (</span>3,0), this means it touches the x-axis at that point. hope this helps
- Ava<3
