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andreyandreev [35.5K]
3 years ago
12

Which situation is best represented by the equation below?

Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:

John paid $127 for football camp. He paid a $7 registration fee and $5 for each week he was enrolled in camp. What is w, the number of weeks John was enrolled in football camp?

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A receipe for cupcakes call for 2/3 cup of chocolate chips for a batch of two dozen cupcakes. How many chocolate chips will be n
balu736 [363]
1/3 and 1/6 a cup for the total amount of chocolate chip cookies needed. Hope this helped! :)
6 0
4 years ago
A 50-gal tank initially contains 20 gal of pure water. Salt- water solution containing 0.5 lb of salt for each gallon of water b
icang [17]

Answer:

x(15) = 21 lb

Step-by-step explanation:

Rate of change in volume of salt water solution = rate of volume incoming - rate of volume outgoing

                                dV/dt  = 4 - 2 =2gal/min

So, the equation for volume at cetain time t at given conditions and values becomes,

                                V(t) = 2t + V

                                V(t) = 2t + 20   gal-------------------euqation (1)

Rate of change in amount of salt = rate of salt in - rate of salt out

                                  dx/dt = {0.5*4} - {[x(t)/V(t)]*2}

                                  dx/dt = 2-2[(x(t))/(2t+20)]

                                  dx/dt = 2-[(x(t))/(v(t))] lb/min

Now, with integrating factor, we get

          exp[∫(1/(1+10))dt)] = t+10

the equation becomes

(t + 10)*x' + x = 2*(t+10)

((t+10)*x') = 2*(t+10)

(t+10)*x = t² + 20t + C

As x(0) = 0,

x(t) = (t²+20t)/(t+10)

x(15) = (15²+20*15)/(15+10)

x(15) = 21 lb

4 0
3 years ago
I know you add it but can you please help and show work
kondaur [170]
Answer is b i know this
5 0
4 years ago
Can sum1 add me as a friend? I need some;'(
OlgaM077 [116]

Answer:

do we have an issue good sir?

≤))≥

_| \_

yall are DOWN BAD asking to get friends on a app like this l m a o

3 0
3 years ago
HELP ASAP!!! LOTS OF POINTS!
aleksklad [387]

Answer:

You can use the formula for the perimeter of a square to find the length of one of the square's sides. Then substitute that information into the formula for the area of a square and solve.

Step-by-step explanation:

Taking the exam same as you 90 % sure this is right

7 0
4 years ago
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