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padilas [110]
3 years ago
15

Goedele adds 52g of flour to her cake mix.

Mathematics
2 answers:
VLD [36.1K]3 years ago
7 0

52 \times 2 = 104

The recipe told her to add 104 g of flour

//

Proof:

104 \times 0.50 = 52

jolli1 [7]3 years ago
3 0
26g cuz math is awesome
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In 2015, the population of a district was 10,600. With an annual growth rate of approximately 4%, what will the population be in
Murljashka [212]

Answer:

19,090\ people

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

y=a(1+r)^x

where

y is the population

x is the time in years since year 2015

a is the initial value

r is the rate of change

we have

a=10,600\\r=4\%=4/100=0.04

substitute

y=10,600(1+0.04)^x

y=10,600(1.04)^x

In the year 2040 the value of x is equal to

x=2040-2015=25\ years

substitute

y=10,600(1.04)^{15} =19,090\ people

7 0
3 years ago
Mayerlin has a mask collection of 400 masks. She keeps some in a display case and the rest on the wall. She keeps 24% of her mas
mariarad [96]

The number of masks that Mayerlin kept on her wall given the information in the question is 304.

<h3>What are percentages?</h3>

Percentage is the fraction  of an amount that is usually expressed as a number out of hundred. Percentages are a measure of frequency.

<h3>How many masks are on the wall?</h3>

Percentage of the masks on the wall = 100 - 24 = 76%

Number of the masks on the wall = 76% x 400 = 304

To learn more about percentages, please check: brainly.com/question/25764815

4 0
2 years ago
Givea)Possible number of positive real rootsb)Possible number of negative real rootsc)Possible rational roolsd)Find the roots
CaHeK987 [17]

The function is given to be:

x^3-2x^2-3x+6

QUESTION A

We can use Descartes' Rule of Signs to check the positive real roots of a polynomial.

The rule states that if the terms of a single-variable polynomial with real coefficients are ordered by descending variable exponent, then the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients, or is less than it by an even number.

If we have:

f(x)=x^3-2x^2-3x+6

The coefficients are: +1, -2, -3, +6.

We can see that there are only 2 sign changes; from the first to the second term, and from the third to the fourth term.

Therefore, there are 2 or 0 positive real roots.

QUESTION B

To find the number of negative real roots, evaluate f(-x) and check for sign changes:

\begin{gathered} f(-x)=(-x)^3-2(-x)^2-3(-x)+6 \\ f(-x)=-x-2x^2+3x+6 \end{gathered}

The coefficients are: -1, -2, +3, +6.

We can see that there is only one sign change; from the second term to the third term.

Therefore, there is 1 negative real root.

QUESTION C

To check the possible rational roots, we can use the Rational Root Theorem since all the coefficients are integers.

The Rational Root Theorem states that if the polynomial:

P(x)=a_nx^n+a_{n-1}x^{n-1}+\cdots+a_2x^2+a_1x+a_0

has any rational roots, they must be in the form:

\Rightarrow\pm\mleft\lbrace\frac{factors\text{ of }a_0}{factors\text{ of }a_n}\mright\rbrace

From the polynomial, the trailing coefficient is 6:

a_o=6

Factors of 6:

\Rightarrow\pm1,\pm2,\pm3,\pm6

The leading coefficient is 1:

a_n=1

Factors of 1:

\Rightarrow\pm1_{}

Write in the form

\Rightarrow\mleft\lbrace\frac{a_o}{a_n}\mright\rbrace

Therefore,

\Rightarrow\pm(\frac{1}{1}),\pm(\frac{2}{1}),\pm(\frac{3}{1}),\pm(\frac{6}{1})

Therefore, the possible rational roots are:

\Rightarrow\pm1,\pm2,\pm3,\pm6

QUESTION D

We can use a graph to check the roots of the polynomial. The graph is shown below:

The roots of the polynomial refer to the points when the graph intersects the x-axis.

Therefore, the roots of the polynomial are:

x=-1.732,x=1.732,x=2

7 0
2 years ago
What is the solution set of the inequality | 8x + 3| &lt; 1 ?
Dmitry [639]

Answer: x < - 1/4 and x > - 1/2

u juss solve for your inequality step-by-step.

4 0
4 years ago
72.1 written as a fraction
kaheart [24]
It is 72 1/10. This is because 72 is a whole number and point one would be tenths.
5 0
4 years ago
Read 2 more answers
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