Answer:
Step-by-step explanation:
<u>Let the integers be:</u>
- n, n + 1, n + 2 and n + 3
<u>Their sum is 114:</u>
- n + n + 1 + n + 2 + n + 3 = 114
<u>Solving for n:</u>
- 4n + 6 = 114
- 4n = 108
- n = 108/4
- n = 27
<u>The numbers are:</u> 27, 28, 29 and 30
Easiest way is to find out first how many she runs in a week. For that you can multiply the number of hours she runs a weekday by 5. (3.2*5) That should be 16. Now, since you want to know how many miles she will run in a span of 6 weeks you must multiply it by 6 now. That is 96. Since you know that, let's move on to the weekends. It is 1.5 per weekend day or 3 per weekend. Now you have to multiply 3 by 6 because you want to know for six weeks. Since you have both your numbers now, 18 and 96, you can add them to make a final of 114.
Answer:
Joe is 14.
Martha is 28.
Step-by-step explanation:
Use the variables and information from the question to make equations.
If Joe's age is half Martha's:
(1/2)m = j OR 2j = m
If their ages combined is 42:
m + j = 42
We can substitute the equation m=2j into equation m + j = 42, replacing "m".
m + j = 42 Substitute m for 2j
2j + j = 42 Combine like terms, terms with same varables
3j = 42 Divide both sides by 3 to isolate j
j = 14 Joe's age
Since j = 14, we can substitute it into equation m=2j to find "m".
m = 2j Substitute j for 14
m = 2(14) Simplify
m = 28 Martha's age
Therefore Joe is 14 and Martha is 28.
Rate = distance / time
Rate = 21 miles / 3 hours
Rate = 7 miles / hour
The answer is choice A. Hope this helps.
