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3 years ago

What is the domain of the function? f(x) square root of x+1 over (x+4)(x-6)

Mathematics

1 answer:

Radda [10]3 years ago

5 0

Answer:

[-1,6)U(6, ∞)

Step-by-step explanation:

$f(x) = \frac{\sqrt{x+1}}{(x+4)(x-6)}\\$

In functions that have a square root, the radicand (the inside of the root) has to be ≥0. Otherwise, you would be dealing with imaginary numbers.

So, in our function,

$x+1 \geq0\\x\geq-1$

We have two factors in our denominator. Note that you cannot divide by 0. So to find where x cannot be, we have to set the denominator to 0.

$(x+4)(x-6)=0\\x+4=0 \\x-6 = 0\\\\x=-4\\x=6$

X cannot be either -4 or 6.

So, x has to be greater than or equal to -1 and cannot equal -4 or 6.

x≥-1, x≠6

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Answer:

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3 years ago

For the function y = -2+5sin(pi/12(x-2)), what is the maximum value?

myrzilka [38]

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dy/dx = 5 pi/12 cos(pi/12 (x-2))

Equate to zero:
5 pi/12 cos(pi/12 (x-2)) =0
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2 years ago

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Answer:

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Step-by-step explanation:

Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.

$Dom\{f\} = [0\,m,5\,m]$

$Ran\{f\} = [0\,m^{2}, 10\,m^{2}]$

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2 years ago

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yaroslaw [1]

Answer:

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