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nadya68 [22]
2 years ago
10

Please help me the formula A=1/2 X bX h

Mathematics
1 answer:
grin007 [14]2 years ago
4 0

Answer:

−4 cot ( −45 )

Step-by-step explanation:

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What is the distance between (–4, –10) and (–4, –4)?
Gre4nikov [31]

Answer:

6 units

Step-by-step explanation:

(-4 , -10) ; (-4 , -4)

Distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

               = \sqrt{(-4-[-4])^{2}+(-4-[-10])^{2}}\\\\= \sqrt{(-4+4)^{2}+(-4+10)^{2}}\\\\=\sqrt{0+(6)^{2}}\\\\= \sqrt{36}\\\\= 6

4 0
2 years ago
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How to divide 453 by 8 in standard form
Leno4ka [110]

Answer:

56 5/8

Step-by-step explanation:

     453/8

8 0
2 years ago
The pipe is leaking at 1.5 cups per day about how many gallons per week is the population
Inessa [10]
The question asks per week. So 1.5 cups times 7 days is 10.5 cups. 

The pipe leaks 10.5 cups every week.
6 0
3 years ago
Which two answers???
Norma-Jean [14]

Answer:

B and D

Step-by-step explanation:

have a nice day and mark me brainliest! :)

6 0
3 years ago
You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and
Llana [10]

Answer:

Hence the adjusted R-squared value for this model is 0.7205.

Step-by-step explanation:

Given n= sample size=20  

Total Sum of square (SST) =1000  

Model sum of square(SSR) =750  

Residual Sum of Square (SSE)=250  

The value of R ^2 for this model is,  

R^2 = \frac{SSR}{SST}  

R^2 = 750/1000 =0.75  

Adjusted R^2 :

Adjusted R^2 =1- \frac{(1-R^2)\times(n-1)}{(n-k-1)}

Where k= number of regressors in the model.

Adjusted R^2 =1-(19\times 0.25/((20-2-1)) = 0.7205

3 0
2 years ago
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